Boats and Streams Example 2

Shortcut tricks on boats and streams are one of the most important topics in exams. Time is the main factor in competitive exams. If you know time management then everything will be easier for you. Most of us skip that part. Few examples on boats and streams shortcuts is given in this page below. These shortcut tricks cover all sorts of tricks on Boats and Streams. Visitors are requested to carefully read all shortcut examples. These examples here will help you to better understand shortcut tricks on boats and streams.

Before starting anything just do a math practice set. Then find out twenty math problems related to this topic and write those on a paper. Using basic math formula do first ten maths of that page. You also need to keep track of the time. After finish write down total time taken by you to solve those ten maths. Now practice our shortcut tricks on boats and streams and read examples carefully. After doing this go back to the remaining ten questions and solve those using shortcut methods. Again keep track of timing. You will surely see the improvement in your timing this time. But this is not all you want. If you need to improve your timing more then you need to practice more.

Math section in a competitive exam is the most important part of the exam. It doesn’t mean that other topics are not so important. But if you need a good score in exam then you have to score good in maths. You can get good score only by practicing more and more. All you need to do is to do math problems correctly within time, and this can be achieved only by using shortcut tricks. But it doesn’t mean that you can’t do math problems without using any shortcut tricks. You may have that potential that you may do maths within time without using any shortcut tricks. But so many people can’t do this. So Boats and Streams shortcut tricks here for those people. We try our level best to put together all types of shortcut methods here. But it possible we miss any. We appreciate if you share that with us. Your help will help others.

This is the basic theory of Boat and Stream which is applied in question to obtain answers here Boat and Stream Methods of example in different form of examples.

In maths exam papers there are two or three question are given from this chapter.This type of problem are given in Quantitative Aptitude which is a very essential paper in banking exam.Under below given some more example for your better practice.

 

 

Example 1: A fisherman running upstream and covers 16km and running downstream and covers 28km taking 6 hours each time. Find the velocity of water current.
Answer : let fisherman running speed in still water is u km/hr.
Speed of of current is v km/hr
So, Speed of downstream is (u + v)
Speed of upstream is (u – v)
So, 6(u – v) = 16 and 6(u + v) = 28
6u + 6v = 28
6u – 6v = 16
Subtracting we get
12v = 12
v = 1 km/hr.

 

 

Example 2: A boy can row 4 km against the stream in 24 minutes and back in 20 minutes. What would be the rate of current ?
Answer : Speed of boy upstream 4 km in 24 minutes = 4 x 60 / 24 = 10 km/hr.
Speed of boy downstream 4 km in 20 minutes = 4 x 60 / 20 = 12 km/hr.
So, Rate of current is 1 / 2 (downstream – upstream) = 1 / 2 (12 – 10) = 1 km/hr.

 

 


Example 3:

Find the speed of current and speed of Sharmistha in still water .when Sharmistha can go 40Km / hr upstream and 54Km / hr downstream ?
Answer :
upstream speed is = 40Km / hr and downstream speed is = 54 Km / hr.So,
Speed of a current
= U – V / 2
= 54 – 40 / 2 = 14 / 2 = 7 Km /hr.
So Speed of current 7Km / hr.
Speed of main in still water
U+V /2 = 54 + 40 / 2 = 47 Km / hr.
Speed of main in still water is 47Km / hr.

 

 

Example 4:
A small ship covers a certain distance downstream in 1 hour ,when it comes back in 3 /2 hours . If the speed of the stream be 4 km/hr ,
what is the speed of the boat in still water ?
Answer :
Suppose the speed of the ship in still water be x km/hr , Then
speed of downstream = ( x + 4 ) km /hr .
speed of upstream =  ( x – 4 ) km /hr .
So , ( x + 4 ) x 1 =  ( x – 4 ) x 3 / 2
2x + 8 = 3x – 12
= 3x – 2x = -12 – 8
= x = 20 km /hr .

 

 

 Example 5:
Jonnycan row a certain distance downstream in 8 hours and upstream the distance in 10 hours , If the stream flows rate at of 4 km / hour then , Find the speed of jonny in still water .
Answer :
Speed of jonny in still water be z km /hr
downstream speed = ( u – v)
upstream speed = ( u + v)
Shortcut tricks :
Speed of jonny in still water is =
rate ( upstream speed + downstream speed /  upstream speed – downstream speed )
4 ( 10 + 8 ) / 10 – 8 = 36 km / hr .

 

 

 

 

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