Shortcut Tricks are very important things in competitive exam. Competitive exams are all about time. If you know time management then everything will be easier for you. Most of us miss this thing. We provide examples on Mixture and Alligation shortcut tricks here in this page below. We try to provide all types of shortcut tricks on mixture and alligation here. Visitors please read carefully all shortcut examples. These examples here will help you to better understand shortcut tricks on mixture and alligation.
Before doing anything we recommend you to do a math practice set. Then find out twenty math problems related to this topic and write those on a paper. Solve first ten math problems according to basic math formula. You also need to keep track of Timing. After solving all ten math questions write down total time taken by you to solve those questions. Now practice our shortcut tricks on mixture and alligation and read examples carefully. After finishing this do remaining questions using Mixture and Alligation shortcut tricks. Again keep track of timing. You will surely see the improvement in your timing this time. But this is not all you want. You need more practice to improve your timing more.
Math section in a competitive exam is the most important part of the exam. That doesn’t mean that other sections are not so important. You can get a good score only if you get a good score in math section. A good score comes with practice and practice. You should do your math problems within time with correctness, and this can be achieved only by using shortcut tricks. But it doesn’t mean that without using shortcut tricks you can’t do any math problems. You may have that potential to do maths within time without using any shortcut tricks. But other peoples may not do the same. For those we prepared this mixture and alligation shortcut tricks. Here in this page we try to put all types of shortcut tricks on Mixture and Alligation. But if you see any tricks are missing from the list then please inform us. Your help will help others.
Mixture and Alligation Examples
Here in this Mixture and Alligation Methods and some important formula which need to understand through examples 2 that are given in exams. we provide u some example 2 based on mixture and Alligation. This is the basic theory of Mixture and Alligation which is applied in question to obtain answers here Mixture and Alligation Methods of example in different form of examples.
In maths exam papers there are two or three question are given from this chapter. This type of problem are given in Quantitative Aptitude which is a very essential paper in banking exam. Under below given some more example for your better practice.
Example #1
Two vessels A and B contains spirit and water mixed in the ratio of 7 : 6 and 4 : 3 respectively. These mixture be mixed to get a new mixture containing 600 / 13 % spirit, is?
- 10 : 7
- 10 : 3
- 3 : 11
- 5 : 13
Show Answer Show How to Solve Open Rough Workspace
Let, the cost of 1 liter Spirit Rs.1/-.
Spirit in 1 liter mixture of A = 7 / 13 liter,
Cost price of 1 liter mixture of A = Rs.7 /13.
Spirit in 1 liter mixture in B = 4 / 7 liter,
Cost price of 1 liter mixture in B = Rs. 4 / 7.
So, spirit in 1 liter of new mixture is,
= 600 x 1 x 1 / 13 x 100
= 6 / 13 liter (Mean price).
Using the rule of alligation, we have:
So, the required ratio is
10 / 91 : 1 / 13
= 10 : 7
Example #2
In 400 gm of a mixture there was 30% of rice in it. How much rice should be added to make it 50% in the mixture?
- 160 gm
- 180 gm
- 200 gm
- 225 gm
Show Answer Show How to Solve Show Shortcut Tricks Open Rough Workspace
The existing solution has 30% rice.
So, the other solution has 100% rice,
Formula applied:
Quantity of cheaper / Quantity of dearer = CP of dearer – Mean price / Mean price – CP of cheaper
100 – 50 / 50 – 30
= 50 / 20
= 5 : 2.
So, the two mixtures be added in the ratio of 5 : 2.
Required rice is,
= 400 x 2 / 5
= 160 gm.
Solution ( Required % value – Present % value ) / ( 100 – Required % value )
400 ( 50 – 30 ) / 100 – 50
= 160 gm.
Example #3
In what ratio stone be mixed with rice so as to gain 40% by selling at cost price?
- 1 : 4
- 2 : 5
- 3 : 5
- 4 : 7
Show Answer Show How to Solve Open Rough Workspace
Let, cost price of pure rice is Rs.1/-.
Sell price of mixture is Rs.1/-.
And, % profit = 40%.
Sp, cost price in the mix is,
1 X 100 / 140
= 5 / 7.
Now, by applying alligation formula:
Cost price 1 = 1(rice).
Cost price 2 = 0(stone).
Mean price (mix) = 5 / 7.
( Cost price 1 – Mean price ) : ( Cost price 2 – Mean price )
= 2 / 7 : 5 / 7
= 2 : 5.
So, the ratio between rice and stone to gain 40% Profit is 2 : 5.
Few examples of Mixture and Alligation with Shortcut Tricks
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Very well
Its hapy to give these wonderful shortcuts but some more solutions should be given for better understanding
You are right
Very well
Coudn’t understand the solution…can you please elaborate it.
well done..thanks a lot MST team..
good work sir,please continue
Thanks a lot
Thanks for making it easy to understand
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