More than one Quadratic equations shortcut tricks are very important thing to know for your exams. Competitive exams are all about time. If you know time management then everything will be easier for you. Most of us miss this thing. Few examples on more than one quadratic equations shortcuts is given in this page below. We try to provide all types of shortcut tricks on more than one quadratic equations here. Visitors please read carefully all shortcut examples. You can understand shortcut tricks on More than one Quadratic equations by these examples.

First of all do a practice set on math of any exam. Choose any twenty math problems and write it down on a page. Using basic math formula do first ten maths of that page. You also need to keep track of timing. After finish write down total time taken by you to solve those ten maths. Now go through our page for more than one quadratic equations shortcut trick. After doing this go back to the remaining ten questions and solve those using shortcut methods. Again keep track of Timing. The timing will be surely improved this time. But this is not enough. You need more practice to improve your timing more.

We all know that the most important thing in competitive exams is Mathematics. It doesn’t mean that other topics are not so important. But only math portion can leads you to a good score. A good score comes with practice and practice. The only thing you need to do is to do your math problems correctly and within time, and you can do this only by using shortcut tricks. Again it does not mean that you can’t do maths without using shortcut tricks. You may have that potential to do maths within time without using any shortcut tricks. But so many other people may not do the same. So More than one Quadratic equations shortcut tricks here for those people. We try our level best to put together all types of shortcut methods here. But we may miss few of them. If you know anything else rather than this please do share with us. Your little help will help others.

**More than one Quadratic equations**

In this type quadratic equation has more than two equations are given. we need to solve both the equations individually.

In maths exam papers there are two or three question are given from this chapter. This type of problem are given in Quantitative Aptitude which is a very essential paper in banking exam. Under below given some more example for your better practice.

In More than one quadratic equation has maximum power of unknown variable has two.

**Example:** ax^{2} + bx + c = 0

**Example:** mx^{2} + nx + p = 0

it is equal to 0 and the a, b, c are the constant value and we can say that x represent as unknown.

it is equal to 0 and the m, n, p are the constant value and we can say that x represent as unknown.

The a , b , c are the constant and quadratic coefficient or linear coefficient. Quadratic equation hold the only power of x which is also non negative integer. same in equation mx2 + nx + p = 0

Before going to solve you first solve the both equation first than chose the given answer following option.

**x>y****x>y****x<y****x<y****x = y relation can not be determined.**

- 5x
^{2}+ 11x + 6 = 0 - 4y
^{2}+ 10y + 6 = 0

In equation one multiply 5 and 6 get the result is 30 separate 30 as 5 and 6 which is addition of 5+6=11.

In equation two multiply 4 and 6 get the result is 24 separate 24 as 4 and 6 which is addition of 4+6=10.

and switch the sign in to negative and divide by coefficient of x^{2}. -5 / 5 = -1 and -6 / 5 = -6 / 5.

and the second equation is do same that is -4 / 4 = -1 and -6 / 4 = -3 / 2.

Now we get the solution is for x = -1 and -6 / 5.

Now we get the solution is for y = -1 and -3 / 2.

- Linear equations
- One variable linear equations
- More than one variable linear equations
- Quadratic equations
- Single variable Quadratic equations
- << Go back to Inequality Methods main page

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how to choose the answers wen x_> y or y>_ x

how to choose answer

depends on sign and value suppose, x = 4, -1/2

y = -5/2, -3/2

so, x>y because 4 is greater than y like -5/2, -4/2 and -1/2 is greater than -5/2, -3/2.

then,

1)x=-5, 4

y=-5, 6

2)x= -5, 6

y= 4, 6

what is the relation betwn x nd y, when they are like this

In this case relationship cannot be established since one value of x is grtr and other smaller dan y

x<=y

for instance one no. is greater n another, what would we do

suppose x=1 and 5 and y =1 and -1 than in this case x_>y

what are the roots of 2x square-11s-76=0

19/2, -4

-8/11,19/11

There any chance to find the answer from given choice ….

Please explain some examples for x=y and x=y or relation can’t be determined cases

Aftr solving the roots, Place the values of X and Y in number line

Then check for x and y values

1. If all X is on the rightside of Y its X> Y

2. If all Y is on the rightside of X its Y>X

3. If the values of X and Y Crossover its other it’s relation can’t be determined

Explain how to choose the answer?

Some times it is very difficult to find multiply of constant no that fullfill condition of middle term…any trick for it

For ex.

1). 7Xsquare -29x+30=0

Via short trick How to find multiply of 210

2). 4Xsquare-36X+81

7x^2 – 29x – 30

Trick:+7 x -30 = -210 = -35 + 6

change sigh and divided it by coefficient of x = + 35 / 7 = +5, – 6 / 7 = – 6 / 7.

Sir plz explain how to compare the values of x and y ?

Sir plz explain how to chose the ans and how to compare the valus of x and y ? Plz i can solve the values but unable to conpare ?

How to solve 8x^2+ 31x+21=0???

thanku for all this tricks its very helpful

Pls solve it 6x^2+5x+1=0,15y^2+8y+1=0 than which one is correct a)y>x b)y>_x

6×2+5x+1 ,15y2+8y+1 solved it Which one y>x ,y>~x

Solve it 6x^2+5x+1=0 ,15y^2+8y+1=0. Which one is correct a) y>x b) y>~x

X^2-19X+84=0,Y^2-25Y+156=0

relation between X and Y?

If question says

Y^2-9y+20 plc calculate

8x^2+42x+27=0

15y^2+43y+30=0

How can v solve this in short period of time ??

I read somewhere there is a trick by which we can ans just by looking the signs of two equations. Can u pls mention that trick ??

how can I solve this in short period of time

12x^2-55x+63= 0

4y^2-17y+18=0