## Permutation examples 1 with tricks

Shortcut Tricks are very important things in competitive exam. Time is the main factor in competitive exams. If you know time management then everything will be easier for you. Most of us miss that part. Here in this page we give few examples on Permutation shortcut tricks. We try to provide all types of shortcut tricks on permutation here. We request all visitors to read all examples carefully. These examples will help you to understand shortcut tricks on Permutation.

Before starting anything just do a math practice set. Choose any twenty math problems and write it down on a page. Do first ten maths using basic formula of this math topic. You also need to keep track of timing. After solving all ten math questions write down total time taken by you to solve those questions. Now go through our page for permutation shortcut trick. After doing this go back to the remaining ten questions and solve those using shortcut methods. Again keep track of the time. This time you will surely see improvement in your timing. But this is not all you want. You need to practice more to improve your timing more.

### Few things to Remember

Math section in a competitive exam is the most important part of the exam. That doesn’t mean that other topics are less important. You can get a good score only if you get a good score in math section. You can get good score only by practicing more and more. All you need to do is to do math problems correctly within time, and only shortcut tricks can give you that success. Again it does not mean that you can’t do maths without using shortcut tricks. You may do math problems within time without using any shortcut tricks. You may have that potential. But so many people can’t do this. For those we prepared this permutation shortcut tricks. Here in this page we try to put all types of shortcut tricks on Permutation. But we may miss few of them. If you know anything else rather than this please do share with us. Your little help will help so many needy.

We learn** what is permutation ?** so now we need more knowledge on this using more practice examples 1 of permutation with tricks which help in exams fast and efficiently. Again we talk about permutation that permutation is a various or several given arrangement of numbers or several things where we taking some or all at a time. Here is some examples are given below,

Example #1

How many words can be formed with the letters of the word “EQUATIONS”?

- 305689
- 338668
- 362880
- 385568

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (C)

**How to Solve**

The word EQUATIONS contains 9 letters.

Required number of word using formula,

^{n}P

_{n}= n!

“EQUATIONS” = 9!

= 362880

**Rough Workspace**

Example #2

In how many different ways the words “HOUSE” can be arranged?

- 120
- 130
- 140
- 150

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (A)

**How to Solve**

The word HOUSE contains 5 letters.

Required number of word using formula,

^{5}P

_{5}

= 5!

= ( 1 x 2 x 3 x 4 x 5 )

= 120.

**Rough Workspace**

Example #3

In how many different way the word “WORLD” can be arranged?

- 104
- 112
- 118
- 120

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (D)

**How to Solve**

The word WORLD contains 5 letters.

Required number of word using formula,

^{5}p

_{5}

= 5!

= ( 1 x 2 x 3 x 4 x 5 )

= 120.

**Rough Workspace**

Example #4

In how many different way the words “COMPUTER” can be arranged?

- 38576
- 40320
- 42675
- 44779

Show Answer Show How to Solve Show Shortcut Tricks Open Rough Workspace

**Answer:**Option (B)

**How to Solve**

The word COMPUTER contains 8 letters. Here is no repeated word.

So, Required number of word using formula,

^{8}P

_{8}

= 8!

= ( 1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 )

= 40320.

**Shortcut Tricks**

8!

= 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1

= 40320.

**Rough Workspace**

Example #5

In how many different ways the words ‘KOLKATA’ can be arranged?

- 1064
- 1260
- 1488
- 1643

Show Answer Show How to Solve Show Shortcut Tricks Open Rough Workspace

**Answer:**Option (B)

**How to Solve**

The word KOLKATA contains 7 letters.

Here is repeated word occurred.

So, we divided this by repeated word.

Repeated letter ‘K’ two times and ‘A’ two times.

Required number of word using formula.

^{7}P_{7} / ^{2}P_{2} x ^{2}P_{2}

= 7! / 2! x 2!

= ( 7 x 6 x 5 x 4 x 3 x 2 x 1 ) / ( 2 x 1 ) x ( 2 x 1 )

= 1260.

**Shortcut Tricks**

7! / 2! x 2!

= 7 x 6 x 5 x 4 x 3 x 2 x 1 / 2 x 1 x 2 x 1

= 1260.

**Rough Workspace**

### Few examples of Permutation and Combination with Shortcut Tricks

- Examples 2 with tricks
- Examples 3 with tricks
- Combination Methods with tricks
- << Go back to Permutation and Combination Methods main page

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Very nice and consideration