Shortcut Tricks are very important things in competitive exam. Time takes a huge part in competitive exams. If you know how to manage time then you will surely do great in your exam. Most of us skip that part. Here in this page we give few examples on Pipe and Cistern shortcut tricks. These shortcut tricks cover all sorts of tricks on Pipe and Cistern. We request all visitors to read all examples carefully. These examples will help you to understand shortcut tricks on Pipe and Cistern.

Before starting anything just do a math practice set. Choose any twenty math problems and write it down on a page. Solve first ten math problems according to basic math formula. You also need to keep track of the time. Write down the time taken by you to solve those questions. Now go through our page for pipe and cistern shortcut trick. After finishing this do remaining questions using Pipe and Cistern shortcut tricks. Again keep track of the time. The timing will be surely improved this time. But this is not all you want. If you need to improve your timing more then you need to practice more.

You all know that math portion is very much important in competitive exams. That doesn’t mean that other topics are less important. But only math portion can leads you to a good score. You can get good score only by practicing more and more. You should do your math problems within time with correctness, and you can do this only by using shortcut tricks. Again it does not mean that you can’t do maths without using shortcut tricks. You may have that potential that you may do maths within time without using any shortcut tricks. But so many people can’t do this. For those we prepared this pipe and cistern shortcut tricks. We always try to put all shortcut methods of the given topic. But it possible we miss any. We appreciate if you share that with us. Your help will help others.

Pipe and Cistern Example 2

In Pipe and cisterns when we calculate the pipe related examples we first check the nature that if the pipe is filled up by water or any liquid we say the pipe is plus position and when the pipe is vacant we say it as negative, So here we also some example is given. Which help you better understanding.

This type of problem are given in Quantitative Aptitude which is a very essential paper in banking exam . Under below given some more example for your better practice .

Example #1

Two pipes, Pipe 1 and Pipe 2, can fill a water reservoir in 3 hours and 6 hours respectively. Another pipe, Pipe 3, can empty the reservoir in 12 hours. If all the three pipes are opened together, then how many hours will require to fill the water reservoir?

- 9 / 4 Hours
- 11 / 5 Hours
- 12 / 5 Hours
- 13 / 7 Hours

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (C)

**How to Solve**

Net part filled in 1 hour is

[(1 / 3) + (1 / 6)] – (1 / 12)

= 5 / 12.

The water reservoir will be filled in 12 / 5 hours.

**Rough Workspace**

Example #2

If pipe A can fill a water reservoir in 12 hours and pipe B can empty the reservoir in 20 hours. If both pipes are opened simultaneously then how much time will be taken to fill the water reservoir?

- 18 Hours
- 20 Hours
- 24 Hours
- 30 Hours

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (D)

**How to Solve**

Time taken to fill the reservoir in hour = 1 / 12.

Time taken to empty the a reservoir in hour = 1 / 20.

When both pipes are opened then time taken to fill

(1 / 12) – (1 / 20)

= (5 – 3) / 60

= 2 / 60

= 1 / 30.

= 30 hours.

**Rough Workspace**

Example #3

Pipe X can fill the water reservoir in 6 hours. Pipe Y can fill the water reservoir in 10 hours. Pipes Z can fill the water reservoir in 20 hours. If all the Pipes are opened, then in how many hours will the water reservoir be filled?

- 53 / 17 Hours
- 60 / 19 Hours
- 70 / 19 Hours
- 75 / 19 Hours

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (B)

**How to Solve**

Part filled by X in 1 hour = 1 / 6.

Part filled by Y in 1 hour = 1 / 10.

Part filled by Z in 1 hour = 1 / 20.

So, part filled by ( X + Y + Z ) in 1 hour

= (1 / 6) + (1 / 10) + (1 / 20)

= 19 / 60.

So, all the three pipes together will fill the water reservoir in 60 / 19 hours.

**Rough Workspace**

### Few examples of Pipe and Cistern with Shortcut Tricks

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Good

how to find the capacity of the tank when the tank is filled at some rate and emptied at different rate,when both are opened together?

Capacity of tank =rate x time

ONE OF BEST SITES IN THE WEB IT IS.LOTS OF THNX……………..

Its great it helped me very much

pls sove

A pipe p1 can fill one third of the tank in 16 min, pipe 2 fill one sixth of 10 min ,p3 empty one fourth of the 20 min. the tank has leak at the bottom can empty full tank in 4 hr. all 3 pipe are opened when the tank is empty aft hw much time will tank be completed ?

4 hr ha boss

How , shouldn’t it be 48 mins

How , shouldn’t it be 48 mins ???

1/48+1/60-1/80-1/240

1/4(1/12+1/15-1/20-1/60)

5/60*1/4

5/240

1/48

Thus 48 minutes in the answer

Best website I loved it thank u

this is very easy under stand thankyou

sir plz increase the level

Nice

We need more advance level math because competitive examination asking advance math.