## Ratio Example 1

Shortcut Tricks are very important things in competitive exam. Time takes a huge part in competitive exams. If you manage your time then you can do well in those exams. Most of us miss that part. We provide Ratio Example shortcut tricks here in this page below. All tricks on ratio are provided here. Visitors are requested to carefully read all shortcut examples. These examples here will help you to better understand shortcut tricks on ratio.

Before doing anything we recommend you to do a math practice set. Then find out twenty math problems related to this topic and write those on a paper. Do first ten maths using basic formula of this math topic. You also need to keep track of the time. After finish write down total time taken by you to solve those ten maths. Now practice our shortcut tricks on ratio and read examples carefully. After finishing this do remaining questions using Ratio shortcut tricks. Again keep track of Timing. This time you will surely see improvement in your timing. But this is not all you need. You need more practice to improve your timing more.

### Things to Remember

We all know that the most important thing in competitive exams is Mathematics. That doesn’t mean that other sections are not so important. You can get a good score only if you get a good score in math section. You can get good score only by practicing more and more. All you need to do is to do math problems correctly within time, and you can do this only by using shortcut tricks. But it doesn’t mean that you can’t do math problems without using any shortcut tricks. You may do math problems within time without using any shortcut tricks. You may have that potential. But so many other people may not do the same. So Ratio shortcut tricks here for those people. We try our level best to put together all types of shortcut methods here. But if you see any tricks are missing from the list then please inform us. Your little help will help others.

### Ratio Example

Ratio Example shortcut tricks and formula based problem are very important for Competitive exams here is some problems which are given in exams that is some item or product are divide into persons and find the number of item that the person should have, we discuss this example in ratio.

This type of problem are given in Quantitative Aptitude which is a very essential paper in banking exam. Under below given some more Ratio Example for your better practice.

Example #1

If A : B = 7 : 9, C : D = 6 : 13, Then A : B : C = ?

- 21 : 27 : 115
- 42 : 54 : 117
- 44 : 54 : 115
- 21 : 54 : 117

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (B)

**How to Solve**

A : B : C = (7 x 6) : (9 x 6) : (9 x 13) = 42 : 54 : 117

**Rough Workspace**

Example #2

If P : Q : R = 2 : 3 : 4, Then P / Q : Q / R : R / P = ?

- 8 : 9 : 24
- 9 : 8 : 24
- 18 : 19 : 24
- 24 : 9 : 8

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (A)

**How to Solve**

P : Q : R = 2 : 3 : 4

Let P = 2k,

Q = 3k,

R = 4k.

Then,

P / Q = 2k / 3k = 2 / 3

Q / R = 3k / 4k = 3 / 4

R / P = 4k / 2k = 2 / 1.

At first we do LCM.

And LCM of 2, 3, 4 is 12.

Now we multiplied the LCM value with the ratio numbers,

Like, ( 2 / 3 ) x 12 = 8

( 3 / 4 ) x 12 = 9

( 2 / 1 ) x 12 = 24

So, the ratio of P / Q : Q / R : R / P is 8 : 9 : 24

**Rough Workspace**

Example #3

If a : b = 3 : 7 and b : c = 5 : 9, then a : b : c = ?

- 3 : 7 : 63
- 25 : 15 : 36
- 5 : 7 : 9
- 15 : 35 : 63

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (D)

**How to Solve**

A : B = 3 : 7

B : C = 5 : 9

= ( 5 x 7 / 5 ) : ( 9 x 7 / 5 ) = 7 : 63 / 5

= A : B : C = 3 : 7 : 63 / 5 = 15 : 35 : 63

**Rough Workspace**

Example #4

If P : Q = 2 : 3 and Q : R = 4 : 5, then R : P = ?

- 15 : 8
- 8 : 15
- 15 : 12
- 9 : 15

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (A)

**How to Solve**

P / R = ( P / Q x Q / R ) = ( 2 / 3 x 4 / 5 ) = 8 / 15

= R / P = 15 / 8

So, R : P = 15 : 8

**Rough Workspace**

Example #5

If P : Q = 2 : 3, Q : R = 4 : 5 and R : S = 6 : 7, Then P : S = ?

- 8 : 7
- 16 : 35
- 16 : 34
- 14 : 45

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (B)

**How to Solve**

P / S = ( P / Q x Q / R x R / S )

= ( 2 /3 x 4 / 5 x 6 / 7 )

= 16 / 35

So, P : S = 16 : 35

**Rough Workspace**

Example #6

If P : Q = 4 : 3, Q : R = 3 : 5 and R : S = 10 : 9, Then P : Q : R : S = ?

- 9 : 6 : 8 : 10
- 10 : 8 : 6 : 9
- 8 : 6 : 10 : 9
- 6 : 8 : 9 : 10

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (C)

**How to Solve**

P : Q = 4 : 3

Q : R = 3 : 5

R : S =10 : 9

P : Q : R : S = ( 4 x 3 x 10 ) : ( 3 x 3 x 10 ) : ( 3 x 5 x 10 ) : ( 3 x 5 x 9 )

= 120 : 90 : 150 : 135

So, P : Q : R : S = 8 : 6 : 10 : 9

**Rough Workspace**

Example #7

What would be the 3rd proportional to 0.25 to 0.38?

- 0.5776
- 0.6775
- 0.7656
- 0.5677

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (A)

**How to Solve**

0.25 : 0.38 :: 0.38 : X

X = 0.38 x 0.38 / 0.25 = 0.5776

**Rough Workspace**

Example #8

Divide the Rs.520/- in the ratio of 6 : 4 in between Ramesh and Suresh. How much amount would be both are getting?

- 1. Ramesh = 312 and Suresh = 208
- 2. Ramesh = 308 and Suresh = 212
- 3. Ramesh = 208 and Suresh = 312
- 4. Ramesh = 212 and Suresh = 308

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (A)

**How to Solve**

Sum of ratio = ( 6 + 4 ) = 10

Ramesh got his amount = 520 x 6 / 10 = 312

Suresh got his amount = 520 x 4 / 10 = 208

**Rough Workspace**

Example #9

What is the smallest part, If 75 is divided into four parts proportional to 3, 5, 8, 9.

- 9
- 10
- 11
- 12

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (A)

**How to Solve**

Ratio is = 3 : 5 : 8 : 9

Sum of ratio terms is = 25.

So, the smallest part is ( 75 x 3 / 25 ) = 9.

**Rough Workspace**

Example #10

Rama gives his pencils between his four friends Rakesh, Rahul, Ranjan, and Rohit in the ratio 1 / 2 : 1 / 3 : 1 / 4 : 1 / 5. What would be the minimum number of pencils Rama should have?

- 60
- 66
- 77
- 87

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (C)

**How to Solve**

Rakesh : Rahul : Ranjan : Rohit = 1 / 2 : 1 / 3 : 1 / 4 : 1 / 5

At First we need to do the LCM of 2, 3, 4 and 5.

So, LCM of 2, 3, 4, 5 is 60.

Pencils given in ratio among friends are,

Rakesh = ( 1 / 2 x 60 ) = 30

Rahul = ( 1 / 3 x 60 ) = 20

Ranjan = ( 1 / 4 x 60 ) = 15

Rohit = ( 1 / 5 x 60 ) = 12

So, total number of pencils are ( 30 + 20 + 15 + 12 ) = 77.

Rama should have minimum 77 pencils.

**Rough Workspace**

Example #11

Two numbers are respectively 40% and 60% more than third number. What would be the ratio of two numbers?

- 8 : 7
- 7 : 8
- 6 : 7
- 5 : 6

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (B)

**How to Solve**

Let the third number be

**A**

Then first number is 140% of A = 140 x A / 100 = 7A / 5

Second number is 160% of A = 160 x A / 100 = 8A / 5

So, the ratio of first and second number is 7A / 5 : 8A / 5 = 35A : 40A = 7 : 8

**Rough Workspace**

Example #12

A sum of money is divided among P, Q, R, S in the ratio of 2 : 3 : 4 : 7 respectively. If the share of R is Rs.9872 more than the share of P, then what is the total amount of money of Q and S together?

- Rs.43960/-
- Rs.46930/-
- Rs.49630/-
- Rs.49360/-

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (D)

**How to Solve**

Let, P, Q, R and S money respectively is 2x, 3x, 4x, 7x

And share of R is 9872 more than the share of P.

So, R = 4x = P + 9872 = 2x + 9872

4x – 2x = 9872

2x = 9872

x = 4936

Share amount of Q is 4936 x 3 = 14808

Share amount of S is 4936 x 7 = 34552

So, Total amount of Q and S is = Q + S = 14808 + 34552 = 49360

**Rough Workspace**

Example #13

If A : B = 4 : 9 and B : C = 3 : 6, Then find A : C = ?

- 9 : 2
- 2 : 9
- 7 : 9
- 5 : 7

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (B)

**How to Solve**

A / B = 4 / 9 and B / C = 3 / 6

Then, A / C = A / B x B / C

= ( 4 / 9 x 3 / 6 )

= 2 / 9

So, A : C = 2 : 9

**Rough Workspace**

### Few more Ratio Example Number Series

- Example on Ratio 2
- Example Ratio 3
- Examples Ratio 4
- Ratio Hard example 1
- << Go back to Ratio and Proportion main page

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If You Have any question regarding Ratio Example, then please do comment on below section. You can also send us message on facebook.

in ratio example 1, question no.3

ratio given is 3,5,8,9

but substituted value is 2 instead of 9. am i right? and,

regarding the same question. 90 is divided into 3 parts but given is 4 ratios..

clarify..

and your short cuts are very useful..

thanks for your feedback pls recheck the problems ….

a:b=3:7

b:c=5:9 we can solve it,,by using shortcut

a:b = 3:7

b:c= 5:9

a:b:c= 3*5:7*5:7*9

—————-

15:35:63

sir is question me problem hai pls dobara btaenge

konsa problem mention example no….

a:b=3:7

b:c=5:9

a : b :c

3:7:7

5:5:9

Ans 15:35:63

The empty space should be filled by previous number it applies for some type questions

Thank u so much

k / 2 : k / 3 : k / 4 = 6 : 4 : 3?

thank u ankita ..

Please tell me in example 1 how 24 come

At first we do LCM of 2, 3, 4 is 12. now we multiplied with ratio numbers ,

Like, 2 x 12 / 3 = 8

3 x 12 / 4 = 9

2 x 12 / 1 = 24

So,the ratio of P / Q : Q / R : R / P is

8 : 9 : 24Sir p/q:q/r:r/p= 2/3:3/4:2/1= 8:9:24

How 24 came? Plz explain

Lcm of 3,4 is 12. Multiply with 12 to each terms 12×2/3:12×3/4:12×2/1=8:9:24

Can anyone explain Ratio example1of Example4(a:b=3:7,b:c=5:9 find a:b:c)

you can do this way…

a : b = 3 : 7

b : c = 5 : 9

3 x 5 = 15

5 x 7 = 35

7 x 9 = 63

a : b : c = 15 : 35 : 63

Dear Sir Example 4 is so easy using “Preet Ji” method, but I want to know how you do.

Dear Sir, In Example 4 “Preet Ji” Method is so easy but i want to know how u do.

Example 2:

If 2P = 3Q = 4R, Then P : Q : R = ? is incorrect This in very simple terms should be as under; no matter you take k or 1

By taking 2P = 3Q = 4R = 1, we have P = ½ Q= 1/3 and R = ¼

So ratio = ½ : 1/3 : ¼ = 6: 4 : 3 (taking LCM as 12). Ans

I am understand but questions number number 7 no explain right

can any one pls say how the final fraction values of example 1 is converted into whole number

pls check it ….

At first we do LCM of 2, 3, 4 is 12. now we multiplied with ratio numbers ,

Like, 2 x 12 / 3 = 8

3 x 12 / 4 = 9

2 x 12 / 1 = 24

So,the ratio of P / Q : Q / R : R / P is 8 : 9 : 24

example 12 ..9872*9. what is 9?

I don’t know.

Thanks got it

in questn no:3 how u arrived (5*7/5); (9*7/5).Please explain

Plzz.expln.qns no.five

22:24:25

can I get more example sir

sir,

Can u please explain the Example 5 question.

Explain this line:

4*3*10:3*3*10:3*5*10:3*5*9

sir,

Can u please explain the Example 5?

Hey is there any group on WhatsApp???????

sir can u plzz explain eg 9

please explain the example 5

I have one doubt in eg.9 . how the minimum no. of pencils x=1.

please explain how u keep the value of x=1 in eg.9

if a:b=c:d=e:f

then

a+c:b+d =e:f?

As a:b=c:d

=> a=bc/d

Substitute a in a+c = b+d

we get c(b+d)/d = b+d

cancelling b+d on both sides and substitute c/d as e/f or e:f

Thanks

a:b = 2:1 & a:c = 1:3 then a:b:c. ?

please tell me how 140% of A in 9th problem?

sry bro you understood the question wrongly.The first number is 40% greater than A, since the percentage of A should be inside 100%, u took it as 140%.

sir .example 12 .9872*9.

what is 9 ?

i have problem in Q12 .

please explain by detailed steps.

thanks

9 is nothing but, the addition of ratios of p & s which is nothing but the addition of 2+7=9.

VERY USEFUL

sir please bataye 25 kha se aaya

sir please bataye 25 kha se aaya example no.10 mein

I GUESS SOMETHING IS WRONG WITH EXAMPLE 12. Q’s share is 9872 which should be taken as 3x=9872 and hence x=9872/3 am i right? thus share of P and S together is 9x=9*9872/3

if im wrong. plz explain this example sir…

I have a problem with example 12.

Q’s share is 9872 which should be taken as 3x=9872

hence x=9872/3

P and S ‘s share together = 2x+7x=9x=9*9872/3=29616

If im wrong plz do explain sir… waiting for ur reply…

u r right.. same doubt with me. guys please do explain this!

I have a ques…

A and B have marbles 5:7. If B gives 3 marbles to A , then the number of marbles each is same. How many marbles did A have initially???

A will be having 15 marbels

Initially A=5k

B=7k

Now when B gave 3marbles it has 7k-3 and A has 5k+3..….. as both values same equate them

7k-3=5k+3 so k=3 ….so 5k =15

In Example no 12 actual ans is 295290 because 9872 is Q’s share but not total amount to multiply directly is it?

Sir I have problem in ex.12

It should be like this,

3/13×x=9872

X=9872×13/3

But my ans is not match

Plz help me

Thank you

recheck the example 12

q1… ihave doubt pls explain me

I have a doubt in Qs- 9. What is the meaning of smallest part in the questin and why did you multiple with 4 in the last step i.e.

(75/25 )*4

If A:B = 3:2′ then 7A+9B:9A+3B will be