Ratio Example 1


Ratio Example 1

Shortcut Tricks are very important things in competitive exam. Time takes a huge part in competitive exams. If you manage your time then you can do well in those exams. Most of us miss that part. We provide Ratio Example shortcut tricks here in this page below. All tricks on ratio are provided here. Visitors are requested to carefully read all shortcut examples. These examples here will help you to better understand shortcut tricks on ratio.

Before doing anything we recommend you to do a math practice set. Then find out twenty math problems related to this topic and write those on a paper. Do first ten maths using basic formula of this math topic. You also need to keep track of the time. After finish write down total time taken by you to solve those ten maths. Now practice our shortcut tricks on ratio and read examples carefully. After finishing this do remaining questions using Ratio shortcut tricks. Again keep track of Timing. This time you will surely see improvement in your timing. But this is not all you need. You need more practice to improve your timing more.

Things to Remember

We all know that the most important thing in competitive exams is Mathematics. That doesn’t mean that other sections are not so important. You can get a good score only if you get a good score in math section. You can get good score only by practicing more and more. All you need to do is to do math problems correctly within time, and you can do this only by using shortcut tricks. But it doesn’t mean that you can’t do math problems without using any shortcut tricks. You may do math problems within time without using any shortcut tricks. You may have that potential. But so many other people may not do the same. So Ratio shortcut tricks here for those people. We try our level best to put together all types of shortcut methods here. But if you see any tricks are missing from the list then please inform us. Your little help will help others.
 

 

Ratio Example

Ratio Example shortcut tricks and formula based problem are very important for Competitive exams here is some problems which are given in exams that is some item or product are divide into persons and find the number of item that the person should have, we discuss this example in ratio.

This type of problem are given in Quantitative Aptitude which is a very essential paper in banking exam. Under below  given some more Ratio Example for your better practice.

 


Example #1
If A : B = 7 : 9, C : D = 6 : 13, Then A : B : C = ?

  1. 21 : 27 : 115
  2. 42 : 54 : 117
  3. 44 : 54 : 115
  4. 21 : 54 : 117

Show Answer Show How to Solve Open Rough Workspace

Answer: Option (B)
How to Solve
A : B : C = (7 x 6) : (9 x 6) : (9 x 13) = 42 : 54 : 117
Rough Workspace

Example #2
If P : Q : R = 2 : 3 : 4, Then P / Q : Q / R : R / P = ?

  1. 8 : 9 : 24
  2. 9 : 8 : 24
  3. 18 : 19 : 24
  4. 24 : 9 : 8

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Answer: Option (A)
How to Solve
P : Q : R = 2 : 3 : 4
Let P = 2k,
Q = 3k,
R = 4k.
Then,
P / Q = 2k / 3k = 2 / 3
Q / R = 3k / 4k = 3 / 4
R / P = 4k / 2k = 2 / 1.

At first we do LCM.
And LCM of 2, 3, 4 is 12.

Now we multiplied the LCM value with the ratio numbers,
Like, ( 2 / 3 ) x 12 = 8
( 3 / 4 ) x 12 = 9
( 2 / 1 ) x 12 = 24

So, the ratio of P / Q : Q / R : R / P is 8 : 9 : 24

Rough Workspace

Example #3
If a : b = 3 : 7 and b : c = 5 : 9, then a : b : c = ?

  1. 3 : 7 : 63
  2. 25 : 15 : 36
  3. 5 : 7 : 9
  4. 15 : 35 : 63

Show Answer Show How to Solve Open Rough Workspace

Answer: Option (D)
How to Solve
A : B = 3 : 7
B : C = 5 : 9
= ( 5 x 7 / 5 ) : ( 9 x 7 / 5 ) = 7 : 63 / 5
= A : B : C = 3 : 7 : 63 / 5 = 15 : 35 : 63
Rough Workspace

Example #4
If P : Q = 2 : 3 and Q : R = 4 : 5, then R : P = ?

  1. 15 : 8
  2. 8 : 15
  3. 15 : 12
  4. 9 : 15

Show Answer Show How to Solve Open Rough Workspace

Answer: Option (A)
How to Solve
P / R = ( P / Q x Q / R ) = ( 2 / 3 x 4 / 5 ) = 8 / 15
= R / P = 15 / 8

So, R : P = 15 : 8

Rough Workspace

Example #5
If P : Q = 2 : 3, Q : R = 4 : 5 and R : S = 6 : 7, Then P : S = ?

  1. 8 : 7
  2. 16 : 35
  3. 16 : 34
  4. 14 : 45

Show Answer Show How to Solve Open Rough Workspace

Answer: Option (B)
How to Solve
P / S = ( P / Q x Q / R x R / S )
= ( 2 /3 x 4 / 5 x 6 / 7 )
= 16 / 35

So, P : S = 16 : 35

Rough Workspace

Example #6
If P : Q = 4 : 3, Q : R = 3 : 5 and R : S = 10 : 9, Then P : Q : R : S = ?

  1. 9 : 6 : 8 : 10
  2. 10 : 8 : 6 : 9
  3. 8 : 6 : 10 : 9
  4. 6 : 8 : 9 : 10

Show Answer Show How to Solve Open Rough Workspace

Answer: Option (C)
How to Solve
P : Q = 4 : 3
Q : R = 3 : 5
R : S =10 : 9

P : Q : R : S = ( 4 x 3 x 10 ) : ( 3 x 3 x 10 ) : ( 3 x 5 x 10 ) : ( 3 x 5 x 9 )
= 120 : 90 : 150 : 135

So, P : Q : R : S = 8 : 6 : 10 : 9

Rough Workspace

Example #7
What would be the 3rd proportional to 0.25 to 0.38?

  1. 0.5776
  2. 0.6775
  3. 0.7656
  4. 0.5677

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Answer: Option (A)
How to Solve
0.25 : 0.38 :: 0.38 : X
X = 0.38 x 0.38 / 0.25 = 0.5776
Rough Workspace

Example #8
Divide the Rs.520/- in the ratio of 6 : 4 in between Ramesh and Suresh. How much amount would be both are getting?

  1. 1. Ramesh = 312 and Suresh = 208
  2. 2. Ramesh = 308 and Suresh = 212
  3. 3. Ramesh = 208 and Suresh = 312
  4. 4. Ramesh = 212 and Suresh = 308

Show Answer Show How to Solve Open Rough Workspace

Answer: Option (A)
How to Solve
Sum of ratio = ( 6 + 4 ) = 10
Ramesh got his amount = 520 x 6 / 10 = 312
Suresh got his amount = 520 x 4 / 10 = 208
Rough Workspace

Example #9
What is the smallest part, If 75 is divided into four parts proportional to 3, 5, 8, 9.

  1. 9
  2. 10
  3. 11
  4. 12

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Answer: Option (A)
How to Solve
Ratio is = 3 : 5 : 8 : 9
Sum of ratio terms is = 25.

So, the smallest part is ( 75 x 3 / 25 ) = 9.

Rough Workspace

Example #10
Rama gives his pencils between his four friends Rakesh, Rahul, Ranjan, and Rohit in the ratio 1 / 2 : 1 / 3 : 1 / 4 : 1 / 5. What would be the minimum number of pencils Rama should have?

  1. 60
  2. 66
  3. 77
  4. 87

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Answer: Option (C)
How to Solve
Rakesh : Rahul : Ranjan : Rohit = 1 / 2 : 1 / 3 : 1 / 4 : 1 / 5

At First we need to do the LCM of 2, 3, 4 and 5.
So, LCM of 2, 3, 4, 5 is 60.

Pencils given in ratio among friends are,
Rakesh = ( 1 / 2 x 60 ) = 30
Rahul = ( 1 / 3 x 60 ) = 20
Ranjan = ( 1 / 4 x 60 ) = 15
Rohit = ( 1 / 5 x 60 ) = 12

So, total number of pencils are ( 30 + 20 + 15 + 12 ) = 77.
Rama should have minimum 77 pencils.

Rough Workspace

Example #11
Two numbers are respectively 40% and 60% more than third number. What would be the ratio of two numbers?

  1. 8 : 7
  2. 7 : 8
  3. 6 : 7
  4. 5 : 6

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Answer: Option (B)
How to Solve
Let the third number be A
Then first number is 140% of A = 140 x A / 100 = 7A / 5
Second number is 160% of A = 160 x A / 100 = 8A / 5

So, the ratio of first and second number is 7A / 5 : 8A / 5 = 35A : 40A = 7 : 8

Rough Workspace

Example #12
A sum of money is divided among P, Q, R, S in the ratio of 2 : 3 : 4 : 7 respectively. If the share of R is Rs.9872 more than the share of P, then what is the total amount of money of Q and S together?

  1. Rs.43960/-
  2. Rs.46930/-
  3. Rs.49630/-
  4. Rs.49360/-

Show Answer Show How to Solve Open Rough Workspace

Answer: Option (D)
How to Solve
Let, P, Q, R and S money respectively is 2x, 3x, 4x, 7x
And share of R is 9872 more than the share of P.
So, R = 4x = P + 9872 = 2x + 9872
4x – 2x = 9872
2x = 9872
x = 4936

Share amount of Q is 4936 x 3 = 14808
Share amount of S is 4936 x 7 = 34552

So, Total amount of Q and S is = Q + S = 14808 + 34552 = 49360

Rough Workspace

Example #13
If A : B = 4 : 9 and B : C = 3 : 6, Then find A : C = ?

  1. 9 : 2
  2. 2 : 9
  3. 7 : 9
  4. 5 : 7

Show Answer Show How to Solve Open Rough Workspace

Answer: Option (B)
How to Solve
A / B = 4 / 9 and B / C = 3 / 6
Then, A / C = A / B x B / C
= ( 4 / 9 x 3 / 6 )
= 2 / 9

So, A : C = 2 : 9

Rough Workspace

Few more Ratio Example Number Series

 

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57 comments

  1. karthik says:

    in ratio example 1, question no.3
    ratio given is 3,5,8,9
    but substituted value is 2 instead of 9. am i right? and,

    regarding the same question. 90 is divided into 3 parts but given is 4 ratios..

    clarify..
    and your short cuts are very useful..

    • Admin says:

      At first we do LCM of 2, 3, 4 is 12. now we multiplied with ratio numbers ,
      Like, 2 x 12 / 3 = 8
      3 x 12 / 4 = 9
      2 x 12 / 1 = 24
      So,the ratio of P / Q : Q / R : R / P is 8 : 9 : 24

  2. G C rana says:

    Example 2:
    If 2P = 3Q = 4R, Then P : Q : R = ? is incorrect This in very simple terms should be as under; no matter you take k or 1
    By taking 2P = 3Q = 4R = 1, we have P = ½ Q= 1/3 and R = ¼
    So ratio = ½ : 1/3 : ¼ = 6: 4 : 3 (taking LCM as 12). Ans

    • Admin says:

      pls check it ….

      At first we do LCM of 2, 3, 4 is 12. now we multiplied with ratio numbers ,
      Like, 2 x 12 / 3 = 8
      3 x 12 / 4 = 9
      2 x 12 / 1 = 24
      So,the ratio of P / Q : Q / R : R / P is 8 : 9 : 24

    • Sarath says:

      sry bro you understood the question wrongly.The first number is 40% greater than A, since the percentage of A should be inside 100%, u took it as 140%.

  3. suji says:

    I GUESS SOMETHING IS WRONG WITH EXAMPLE 12. Q’s share is 9872 which should be taken as 3x=9872 and hence x=9872/3 am i right? thus share of P and S together is 9x=9*9872/3

    if im wrong. plz explain this example sir…

  4. suji says:

    I have a problem with example 12.
    Q’s share is 9872 which should be taken as 3x=9872
    hence x=9872/3
    P and S ‘s share together = 2x+7x=9x=9*9872/3=29616

    If im wrong plz do explain sir… waiting for ur reply…

  5. Soumi says:

    I have a ques…
    A and B have marbles 5:7. If B gives 3 marbles to A , then the number of marbles each is same. How many marbles did A have initially???

    • Tejaswi says:

      A will be having 15 marbels
      Initially A=5k
      B=7k
      Now when B gave 3marbles it has 7k-3 and A has 5k+3..….. as both values same equate them
      7k-3=5k+3 so k=3 ….so 5k =15

  6. Naveen says:

    I have a doubt in Qs- 9. What is the meaning of smallest part in the questin and why did you multiple with 4 in the last step i.e.
    (75/25 )*4

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