Speed Time and Distance shortcut tricks are very important thing to know for your exams. Time takes a huge part in competitive exams. If you know time management then everything will be easier for you. Most of us miss this thing. Few examples on speed time and distance shortcuts is given in this page below. These shortcut tricks cover all sorts of tricks on Speed Time and Distance. We request all visitors to read all examples carefully. These examples will help you to understand shortcut tricks on Speed Time and Distance.

First of all do a practice set on math of any exam. Choose any twenty math problems and write it down on a page. Solve first ten math problems according to basic math formula. You also need to keep track of the time. After finish write down total time taken by you to solve those ten maths. Now practice our shortcut tricks on speed time and distance and read examples carefully. After this do remaining ten questions and apply shortcut formula on those math problems. Again keep track of the time. The timing will be surely improved this time. But this is not enough. You need more practice to improve your timing more.

We all know that the most important thing in competitive exams is Mathematics. That doesn’t mean that other sections are not so important. You can get a good score only if you get a good score in math section. A good score comes with practice and practice. You should do your math problems within time with correctness, and you can do this only by using shortcut tricks. But it doesn’t mean that you can’t do math problems without using any shortcut tricks. You may have that potential that you may do maths within time without using any shortcut tricks. But so many people can’t do this. So Speed Time and Distance shortcut tricks here for those people. Here in this page we try to put all types of shortcut tricks on Speed Time and Distance. But if you see any tricks are missing from the list then please inform us. Your little help will help so many needy.

Speed Time and Distance Example 1

Here is some example of speed and distance of example 1. This is the basic theory of Speed Time and Distance which is applied in question to obtain answers here is Speed Time and Distance Methods of example 1 in different form of examples. In maths exam papers there are two or three question are given from this chapter.

This type of problem are given in Quantitative Aptitude which is a very essential paper in banking exam. Under below given some more example for your better practice.

Basic formula of Speed and Distance

**Distance = Speed x Time**

**Speed = Distance / Time**

**Time = Distance / Speed**

Example #1

A bus covers a certain distance in 18 hours at the speed of 60 km/hr. What would be the average speed of a bike which covers a distance of 270 km more than the bus in the same time?

- 62 km/hr
- 65 km/hr
- 70 km/hr
- 75 km/hr

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (D)

**How to Solve**

Distance = 60 x 18 = 1080 km.

Speed = (1080 + 270) / 18 = 75 km/hr.

**Rough Workspace**

Example #2

Suresh travel on car and covers 360 km in 8 hours and Ramesh travel on bike and covers 405 km in 9 hours. What would be the sum of there speed?

- 90 km/hr
- 95 km/hr
- 101 km/hr
- 105 km/hr

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (A)

**How to Solve**

Speed of Suresh’s car = 360 / 8 = 45 km/hr.

Speed of Ramesh’s bike = 405 / 9 = 45 km/hr.

So, sum of both their speed = ( 45 + 45 ) = 90 km/hr.

**Rough Workspace**

Example #3

Amir passes a 1200 meter long road in 4 minutes by car. What would be his speed in km/hr?

- 12 km/hr
- 15 km/hr
- 18 km/hr
- 20 km/hr

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (C)

**How to Solve**

Speed = ( 1200 / 4 x 60 ) m / sec = 5m / sec.

Convert it into Km/hr

5 x 18 / 5

= 18 km/hr.

**Rough Workspace**

Example #4

A bullet train covers a certain distance in 40 min. If the train runs at a speed of 45km/hr on an average then the speed at which the train must run to reduce the time of journey to 30 minutes will be?

- 50 km/hr
- 60 km/hr
- 72 km/hr
- 80 km/hr

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (B)

**How to Solve**

Time = 40 / 60 = 2 / 3.

Given speed = 45 km/hr.

Distance = Speed x Time

Distance = 45 x 2 / 3

Distance = 30 km.

Time = 30 / 60

= 1 / 2 hr.

Speed = Distance / Time.

So, the new speed is

30 x 2

= 60 km/hr.

**Rough Workspace**

Example #5

Harish travel to a place by car. For the first 160 km he goes at 64 km/hr and the next 160 km at 80 km/hr. What was his average speed?

- 63.74 km/hr
- 68.23 km/hr
- 71.11 km/hr
- 75.94 km/hr

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (C)

**How to Solve**

Total time taken by Harish is

(160 / 64) + (160 / 80)

9 / 2 hr.

So, the average speed is

320 x 16 / 81

= 71.11 km/hr.

**Rough Workspace**

Example #6

A bike covers a distance of 450 meter in 2 min 30 sec. What is the speed in Km/hr of that bike?

- 10.8 km/hr
- 12.4 km/hr
- 14.9 km/hr
- 17.3 km/hr

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (A)

**How to Solve**

Speed = ( 450 / 150 ) m/sec

= 3 m/sec.

Now convert it into km/hr

3 x 18 / 5

= 10.8 km/hr.

**Rough Workspace**

Example #7

A car covers a certain distance in 7 hours at the speed of 73 km/hr. What should be the average speed of bus which travels a distance of 55 km less than the car in the same time?

- 52.57 km/hr
- 60.34 km/hr
- 65.14 km/hr
- 69.75 km/hr

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (C)

**How to Solve**

The distance covered by the car = ( 73 x 7 ) = 511 km.

The distance covered by bus is

511 – 55 = 456 km.

So, the average speed of the bus is

456 / 7

= 65.14 km/hr.

**Rough Workspace**

Example #8

The speed ratio between two super fast trains is 6 : 8. If the second train runs 600 km in 6 hours, then what would be the speed of the first train?

- 59 Km/hr
- 66 Km/hr
- 72 Km/hr
- 75 Km/hr

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (D)

**How to Solve**

Let, the speed of two trains be 6X and 8X km/hr.

Now, we need to find the value of X,

8X = 600 / 6

8X = 100

X = 100 / 8

X = 12.5.

So, by putting the value of X we get,

( 6 x 12.5 ) km/hr

= 75 Km/hr.

**Rough Workspace**

### Few other examples of Speed Time and Distance

- Speed Time and Distance Example 2
- Speed Time and Distance Example 3
- Speed Time and Distance Example 4
- << Go back to Speed Time and Distance main page

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good

speed=distance /time…..in basic formulae

In Example 1

The answer is 6 km (distance between house and school)

thanks Akhato…

Not do good I want more high level formulas and questions

Speed time and distance is so ridiculous to find videos on how to help me, everytime i go onto youtube there is someone who is indian and i cant understand a freking word so i need someone to make it clear but doesn’t ramble on and on short sweet and simple would be great

i have one problem about time and distance

The distance between two stations , delhi and amritsir is 450 km . A train starts at 4 pm from delhi and moves towards from amritsir at 3.20 pm and moves towards delhiat an average speed of 80 km /hr . How far grom delhi will the two train meet and at what time .

Please forward complete solution in my mail id

please please please sir send me some trick on my email id if you will do as i will heighly oblised every time in my life.

so please send me trick sir ………………..

It was very useful to us

It’s really useful to learners.

to trains which is 127mand 98meter long they runs oposite of each other with the speed of 35 km/hand 55km/h after meting in which tume they cross each other

9 sec

9sec

i like it

the distance between mumbai and delhi is 144o km. two persons A and B started simultaneously from mumbai towards delhi. B took 6hrs less then A to reach delhi. instead , if A travels at twice his speed, he reaches Delhi 6 hours earlier than B. find the speed of B (in kmph).

Please help me with this Question