Average Methods Example3
In average chapter we can say more properly and Enumeration mean is unrectified terms,we can say that average is an sum of n mumber and divided by n.we elaborate this a student score in 35, 56, 65 in three different subjects respectively,than the average score in subject is 35 + 56 + 65 / 3 = 52.So here is some average methods example 3 we discuss. This type of problem are given in Quantitative Aptitude which is a very essential paper in banking exam.Under below given some more example for your better practice.
Example 1:
The average marks acquired by 140 students in a final examination is 36.If the average marks of failed students is 18 and the passed average students is 30.what is the passed students in examination.
Answer :
Number of passed students are = Total students(total average - failed average) / passed average - failed average
Step 1: = 140 ( 36 - 18 ) / ( 30 - 18 )
Step 2: = 210
Example 2:
The average marks of 3 group of 54, 62 and 48 respectively is 60, 65, 70,Then Find the average marks of all the students ?
Answer :
Step 1: At First we find the total students marks according with 3 group = (54 x 60 + 62 x 65 + 48 x 70) = ( 3240 + 4030 + 3360 ) = 10630.
Step 2: Now we need to find average marks (54 + 62 + 48 ) = 164, Required average = 10630 / 164 = 64.81.
Example 3:
Sabir obtained 75,55,89,65 and 45 marks (out of 100) in Economy , Bengali, History, Geography, Environmental science, .What are his average marks.
Answer :
First we add all the obtain number than divide by number of subject,
Average : 75 + 55 + 89 + 65 + 45 / 5 = 65.8
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In average chapter we can say more properly and Enumeration mean is unrectified terms,we can say that average is an sum of n mumber and divided by n.we elaborate this a student score in 35, 56, 65 in three different subjects respectively,than the average score in subject is 35 + 56 + 65 / 3 = 52.So here is some average methods example 3 we discuss. This type of problem are given in Quantitative Aptitude which is a very essential paper in banking exam.Under below given some more example for your better practice.
Example 1:
The average marks acquired by 140 students in a final examination is 36.If the average marks of failed students is 18 and the passed average students is 30.what is the passed students in examination.
Answer :
Number of passed students are = Total students(total average - failed average) / passed average - failed average
Step 1: = 140 ( 36 - 18 ) / ( 30 - 18 )
Step 2: = 210
Example 2:
The average marks of 3 group of 54, 62 and 48 respectively is 60, 65, 70,Then Find the average marks of all the students ?
Answer :
Step 1: At First we find the total students marks according with 3 group = (54 x 60 + 62 x 65 + 48 x 70) = ( 3240 + 4030 + 3360 ) = 10630.
Step 2: Now we need to find average marks (54 + 62 + 48 ) = 164, Required average = 10630 / 164 = 64.81.
Example 3:
Sabir obtained 75,55,89,65 and 45 marks (out of 100) in Economy , Bengali, History, Geography, Environmental science, .What are his average marks.
Answer :
First we add all the obtain number than divide by number of subject,
Average : 75 + 55 + 89 + 65 + 45 / 5 = 65.8
- Average Methods Example 1
- Average Methods Example 2
- Average Methods Example 4
- Average Methods Example 5
- Average Methods Example 6
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We provide few shortcut tricks on this topic. Please visit this page to get updates on more Math Shortcut Tricks. You can also like our facebook page to get updates.
If You Have any question regarding this topic then please do comment on below section. You can also send us message on facebook.
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