Find Compound Interest Tricks
In case of Compound Interest the interest is vary according to time but the first year it is equal that is 1st year Interest is Compound Interest = Simple Interest.But after that year it is increases.So we can find
Compound interest using tricks.
Here is principal is given rate percent and Time is given and find the Compound interest.
Example 1:
Principle is 15000 at rate percent 4% p.c.p.a for 2 years,and compound anually
Find the C.I.
Answer:
We apply the formula to obtain C.I that is C.I = p [(1 + r / 100)n - 1]
P = 15000.
R = 4%.
Time = 2 years.
= 15000 x [( 1 + 4 / 100)2 - 1].
= 15000 x [26x26/25x25 - 1]. [ as we put down (26 / 25)2]
= 15000 x 51 / 625 .
= 1224
Example 2:
The Simple Interest accrued on an amount of Rs.22,500 at the end of 3 years is Rs. 10800.What would be the Compound Interest accrued on the same amount at the same rate at the end of two years ?
Answer :
Here is given amount = 22,500 , Time = Years 3 and S.I = 10800 so we need to find Rate percent.
Step 1: we know S.I = P x R x T / 100
10,800 = 22,500 x R x 3 / 100
R = 1080000 / 67500 = 16 % So R = 16 %.
Step 2: Compound Interest accrued on the same amount at the same rate at the end of two years
is we apply the formula
C.I = 22500 x (116 / 100 x 116 / 100 - 1 )
= 22500 x( 116 x 116/ 10000 - 1) = 22500 x( 13456 / 1000) - 1 = 22500 x (1.3456 - 1) = 22500 x 0.3456 =7776
So the C.I end of two years is 7776.
Example 3:
What will be the compound interest on a sum of Rs.4800/- at the rate of 6 p.c.p.a for 2 years ?
Answer:
Compound Interest = P[1+R/100]n-1
4800[( 1 + 6 / 100 )2 - 1]
4800 [53 x 53 / 50 x 50 - 1 ]
=593.28
So the compound interest is 593.28
Example 4:
What would be the compound interest obtained on an amount of Rs.1,600 at the rate of 8 p.c.p.a after two years ?
Answer:
Amount = SI + Principle
compound Interest = p ( 1 + r / 100)n - 1600
1600 ( 1 + 8 / 100 )2 - 1600
( 1600 x 27 x 27 / 25 x 25 ) - 1600
= ( 1866.24 - 1600 )
= 266.24
Example 5:
What would be the compound interest obtained on an amount of Rs. 6000 at the rate of 10% p.a . after 2 years ?
Answer :
6000[ (1 + 10 / 100) ]n-1
= 6000 [ (11 / 10 )2 - 1]
= 6000 x 21 / 100
= 1260
So the compound interest is 1260.
Example 6:
What would be the compound interest obtained on an amount of Rs.8850 at the rate of 12 p.c.p.a after two years?
Answer :
Amount = 8850
rate = 12
Time = 2 years
compound interest = ?
A = 8850 ( 1 + 12 / 100 )2
= 8850 x 28 x 28 / 25 x 25
= 11101.44
So Amount = Rs.11101.44
C.I = ( 8850 - 11101.44 ) = 2251.44
We provide few shortcut tricks on this topic. Please visit this page to get updates on more Math Shortcut Tricks. You can also like our facebook page to get updates.
If You Have any question regarding this topic then please do comment on below section. You can also send us message on facebook.
In case of Compound Interest the interest is vary according to time but the first year it is equal that is 1st year Interest is Compound Interest = Simple Interest.But after that year it is increases.So we can find
Compound interest using tricks.
Here is principal is given rate percent and Time is given and find the Compound interest.
Example 1:
Principle is 15000 at rate percent 4% p.c.p.a for 2 years,and compound anually
Find the C.I.
Answer:
We apply the formula to obtain C.I that is C.I = p [(1 + r / 100)n - 1]
P = 15000.
R = 4%.
Time = 2 years.
= 15000 x [( 1 + 4 / 100)2 - 1].
= 15000 x [26x26/25x25 - 1]. [ as we put down (26 / 25)2]
= 15000 x 51 / 625 .
= 1224
Example 2:
The Simple Interest accrued on an amount of Rs.22,500 at the end of 3 years is Rs. 10800.What would be the Compound Interest accrued on the same amount at the same rate at the end of two years ?
Answer :
Here is given amount = 22,500 , Time = Years 3 and S.I = 10800 so we need to find Rate percent.
Step 1: we know S.I = P x R x T / 100
10,800 = 22,500 x R x 3 / 100
R = 1080000 / 67500 = 16 % So R = 16 %.
Step 2: Compound Interest accrued on the same amount at the same rate at the end of two years
is we apply the formula
C.I = 22500 x (116 / 100 x 116 / 100 - 1 )
= 22500 x( 116 x 116/ 10000 - 1) = 22500 x( 13456 / 1000) - 1 = 22500 x (1.3456 - 1) = 22500 x 0.3456 =7776
So the C.I end of two years is 7776.
Example 3:
What will be the compound interest on a sum of Rs.4800/- at the rate of 6 p.c.p.a for 2 years ?
Answer:
Compound Interest = P[1+R/100]n-1
4800[( 1 + 6 / 100 )2 - 1]
4800 [53 x 53 / 50 x 50 - 1 ]
=593.28
So the compound interest is 593.28
Example 4:
What would be the compound interest obtained on an amount of Rs.1,600 at the rate of 8 p.c.p.a after two years ?
Answer:
Amount = SI + Principle
compound Interest = p ( 1 + r / 100)n - 1600
1600 ( 1 + 8 / 100 )2 - 1600
( 1600 x 27 x 27 / 25 x 25 ) - 1600
= ( 1866.24 - 1600 )
= 266.24
Example 5:
What would be the compound interest obtained on an amount of Rs. 6000 at the rate of 10% p.a . after 2 years ?
Answer :
6000[ (1 + 10 / 100) ]n-1
= 6000 [ (11 / 10 )2 - 1]
= 6000 x 21 / 100
= 1260
So the compound interest is 1260.
Example 6:
What would be the compound interest obtained on an amount of Rs.8850 at the rate of 12 p.c.p.a after two years?
Answer :
Amount = 8850
rate = 12
Time = 2 years
compound interest = ?
A = 8850 ( 1 + 12 / 100 )2
= 8850 x 28 x 28 / 25 x 25
= 11101.44
So Amount = Rs.11101.44
C.I = ( 8850 - 11101.44 ) = 2251.44
- Find Simple interest based question
- Find The rate % based question
- Find Principle or Sum based question
- Compound Interest shortcut tricks
- << Go back to SI and CI main page
We provide few shortcut tricks on this topic. Please visit this page to get updates on more Math Shortcut Tricks. You can also like our facebook page to get updates.
If You Have any question regarding this topic then please do comment on below section. You can also send us message on facebook.
No comments:
Post a Comment