Problems Based on Present Age Shortcut Tricks

Problems Based on Present Age Shortcut Tricks
Problem based on Present Ages is an very impotant topic which is given most of the competitive exams.You can easily solve all kind of Aptitude questions based on Problems on Present Ages by practicing regularly.Before going to solv the problem on ages you need to know the linear equation which help in math but first you are do traditional process than you learn ages shortcut tricks.



Problems Based on Present Age Shortcut Tricks
Example 1: Ratio of ages of M & N 4 years ago was 3 : 5. If the sum of present ages of M & N is 64 years than , Find the present ages of M & N.

First we do Traditional way than we do shortcut way.
Ans: Let the ages os M & N 4 years ago are 3x and 5x.
Hence, ( 3x + 4 )+( 5x + 4 ) = 64 years, = 8x + 8 = 64, = 8x = 56, x = 7 ( we get the value of x).
So the age of M 4 years ago  = 7 x 3 = 21years, and the age of N 4 years ago = 7 x 5 = 35 years.
Now the present age of M is = ( 21 + 4 ) = 25 years, and present age of N is = ( 35 + 4) = 39 years.

 Problems Based on Present Age Shortcut Tricks:
Example 1: Ratio of ages of M & N 4 years ago was 3 : 5. If the sum of present ages of M & N is 64 years than , Find the present ages of M & N.
Answer :
Step1: M : N = 3 : 5 , According to Question ( P + Q ) = 64 years.Sum of both ages 4 years ago is ( 64 - 8 ) = 56 ,(say that before age thats why subtract)
Step2: M = ( 56 / 8 ) x 3 = 7 x 3 = 21 years and N = (56 / 8 ) x 5 = 5 x 7 = 35 years,
Step3: present age of M = ( 21 + 4 ) = 25 years and present age of N = ( 35 + 4 ) = 39 years.


Example 2:
The total age of gangotri ,sabir, and bibhas is 96 years.10 years ago , the ratio of their ages was 2 : 4 : 5.What is the present age of bibhas?
Answer :
Step 1:Let 10 years before gangotri, sabir, and bibhas ages 3x, 4x, 5x years respectively.
Then ( 2x + 10 ) + ( 4x + 10 ) + ( 5x + 10 ) = 96,
= 11x = 66 = x = 6.
Step 2: Bibhas present age is ( 5x + 10 ) = ( 5 x 6 + 10 ) = 40 years.






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