Pipe Example 1
In Pipe and cisterns is also same as time and work when we calculate the pipe related examples we first check the nature that if the pipe is filled up by water or any liquid we clear consider the pipe is plus and when the pipe is vacant we clear consider it as negative,so here we again describe rule of pipe example and also some example is given.
Remembering points of pipe examples:
Example 1:
Two pipes A and B can fill a tank in 36 hours and 45 hours respectively. If both the pipes are simultaneously, how much time will be taken to fill the tank?
Answer :
Here both pipes are filled so we can easily say it is a positive.
Step 1: So at first of we calculate fill pipe in 1 hours time taken.
A + B together filled a tank in 1 hour = ( 1 / 36 + 1 / 45 ) = 9 / 180 = 1 / 20
Step 2: So in 1 hour it fill with 1 / 20.
hence time taken both the pipe A nad B will fill the tank in 20 hours.
Example 2:
Two pipes A and B can fill a tank in 12 hours and 14 hours respectively while a third pipe C empties the full tank in 30 hours.If all the A, B, C operate simultaneously,How much time will take be filled the tank?
Answer :
Step 1: Net part filled by 1 hour = ( 1 / 12 + 1 / 14 ) - 1 / 30 = 51 / 420.
Step 2: The Time taken will fill the tank is 420 / 51 = 8 hr 12 minutes.
So time taken to fill th etank 8 hr 12 minutes.
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In Pipe and cisterns is also same as time and work when we calculate the pipe related examples we first check the nature that if the pipe is filled up by water or any liquid we clear consider the pipe is plus and when the pipe is vacant we clear consider it as negative,so here we again describe rule of pipe example and also some example is given.
Remembering points of pipe examples:
- If a pipe can fill a tank in x hours, then, part filled by 1 hours = 1 / x.
- If a pipe can empty a tank in y hours, then, part emptied in 1 hours = 1 / y.
- If a pipe can fill a tank in x hours and another pipe can empty the full tank in y hours ( where y>x), then on opening both the pipes, the net part filled in 1 hours = ( 1 / x - 1 / y ).
- If a pipe can fill a tank in x hours and another pipe can empty the full tank in y hours ( where y>x), then on opening both the pipes, the net part emptied in 1 hours = ( 1 / y - 1 / x ).
Example 1:
Two pipes A and B can fill a tank in 36 hours and 45 hours respectively. If both the pipes are simultaneously, how much time will be taken to fill the tank?
Answer :
Here both pipes are filled so we can easily say it is a positive.
Step 1: So at first of we calculate fill pipe in 1 hours time taken.
A + B together filled a tank in 1 hour = ( 1 / 36 + 1 / 45 ) = 9 / 180 = 1 / 20
Step 2: So in 1 hour it fill with 1 / 20.
hence time taken both the pipe A nad B will fill the tank in 20 hours.
Example 2:
Two pipes A and B can fill a tank in 12 hours and 14 hours respectively while a third pipe C empties the full tank in 30 hours.If all the A, B, C operate simultaneously,How much time will take be filled the tank?
Answer :
Step 1: Net part filled by 1 hour = ( 1 / 12 + 1 / 14 ) - 1 / 30 = 51 / 420.
Step 2: The Time taken will fill the tank is 420 / 51 = 8 hr 12 minutes.
So time taken to fill th etank 8 hr 12 minutes.
We provide few shortcut tricks on this topic. Please visit this page to get updates on more Math Shortcut Tricks. You can also like our facebook page to get updates.
If You Have any question regarding this topic then please do comment on below section. You can also send us message on facebook.
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