Time and Work Examples 2
Some important facts are needed for Time and work Problems. If a person do a piece of work which has to be requare more time to complete, and capacity is limited to that person but two or more person do the same piece of work which requare less time and effort is minimum. this examples is two person work a piece of work in same time and find out both person together work to complete.So here is some example 2 of this chapter related which help you better study for job preparation.
Examples 1:
John painted a wall in 6 days of 12 hours each and pal can do it 8 days of 8 hours each. How lengthy will they take do it,working together 36 / 17 hours a day?
Answer :
Step 1: At first we find total work of both per day 12 hours than 6 day he total work ( 6 x 12 ) = 72 hours.
and pal total work is ( 8 x 8 ) = 64 hours.
Step 2: both 1 hour's work is 1 / 72 , 1 / 64.So Both together work in 1 hour's is ( 1 / 72 + 1 / 64 ) = 17 / 576 hour's.
Both finish the work 576 / 17 hour's.
Step 3: number of days of 36 / 17 each = ( 576 / 17 X 17 / 36 ) = 16 days.
So Both together work in 16 days.
Example 2:
Ram and Sam can do a work together to finish in 30 days.They work together in 20 days and then sam left. After another 20 days,A finish the remaining work.In how many days Ram can alone finish the work?
Answer :
Step 1:Ram and Sam can work together in 20 days ( 1 x 20 / 30 ) = 2 / 3 days .Remaining work( 1 - 2 / 3 ) = 1 /3.
Step 2:Now 1 / 3 work is done by Ram in 20 days.
So Whole work done by Ram ( 20 x 3 ) = 60 days.
Example 3:
30 children can complete a piece of work in 50 days. find how many days 15 children can complete the same piece work ?
Answer:
we use ( children x working days ) = ( children x working days )
30 x 50 = 15 x ?
1500 = 15 x ?
? = 100 days
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Some important facts are needed for Time and work Problems. If a person do a piece of work which has to be requare more time to complete, and capacity is limited to that person but two or more person do the same piece of work which requare less time and effort is minimum. this examples is two person work a piece of work in same time and find out both person together work to complete.So here is some example 2 of this chapter related which help you better study for job preparation.
Examples 1:
John painted a wall in 6 days of 12 hours each and pal can do it 8 days of 8 hours each. How lengthy will they take do it,working together 36 / 17 hours a day?
Answer :
Step 1: At first we find total work of both per day 12 hours than 6 day he total work ( 6 x 12 ) = 72 hours.
and pal total work is ( 8 x 8 ) = 64 hours.
Step 2: both 1 hour's work is 1 / 72 , 1 / 64.So Both together work in 1 hour's is ( 1 / 72 + 1 / 64 ) = 17 / 576 hour's.
Both finish the work 576 / 17 hour's.
Step 3: number of days of 36 / 17 each = ( 576 / 17 X 17 / 36 ) = 16 days.
So Both together work in 16 days.
Example 2:
Ram and Sam can do a work together to finish in 30 days.They work together in 20 days and then sam left. After another 20 days,A finish the remaining work.In how many days Ram can alone finish the work?
Answer :
Step 1:Ram and Sam can work together in 20 days ( 1 x 20 / 30 ) = 2 / 3 days .Remaining work( 1 - 2 / 3 ) = 1 /3.
Step 2:Now 1 / 3 work is done by Ram in 20 days.
So Whole work done by Ram ( 20 x 3 ) = 60 days.
Example 3:
30 children can complete a piece of work in 50 days. find how many days 15 children can complete the same piece work ?
Answer:
we use ( children x working days ) = ( children x working days )
30 x 50 = 15 x ?
1500 = 15 x ?
? = 100 days
- Time and work Examples 1
- Time and work Examples 3
- Time and Work Examples 4
- << Go back to Time and Work main page
We provide few shortcut tricks on this topic. Please visit this page to get updates on more Math Shortcut Tricks. You can also like our facebook page to get updates.
If You Have any question regarding this topic then please do comment on below section. You can also send us message on facebook.
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