## Problem on Numbers example 1

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This chapter is based on problem on numbers example 1 and the question are given in the form of a set of Numbers and are in the form of a puzzle form. We just need to examine the given condition and assume the unknown numbers and form equations accordingly. So Here is some Problems based on Numbers which provides you for better practice.

In this page we will discuss some basic ideas of Problem on Numbers. On the basis of these ideas we will learn trick and tips of shortcut problem on numbers.

More you practice then more you learn and keep practice in time. If you think that how to solve problem on numbers questions using problem on numbers shortcut tricks, then further studies will help you to do so.

Example #1

The sum of five consecutive odd numbers is 585. What is the sum of largest and twice the second smallest number?

- 351
- 386
- 419
- 475

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**Answer:**Option (A)

**How to Solve**

Sum of five consecutive odd numbers is 585.

So, the third number is,

585 / 5

= 117.

So, all five odd numbers are,

113, 115, 117, 119 and 121.

Largest odd number is 121.

Twice the second smallest number is (115 x 2) = 230.

So, Sum is,

121 + 230

= 351.

**Rough Workspace**

Example #2

Find the average of the following number of set of scores 297, 845, 453,124, 198, 169.

- 340.4
- 347.5
- 351.9
- 355.5

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**Answer:**Option (B)

**How to Solve**

( 297 + 845 + 453 + 124 + 198 + 168 ) / 6

= 347.5

**Rough Workspace**

Example #3

A customer purchase 8 kg apple per day. How many kg of apple will he order in 4 weeks?

- 206 kg
- 216 kg
- 224 kg
- 232 kg

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**Answer:**Option (C)

**How to Solve**

4 weeks = ( 4 x 7 ) = 28 days.

So, he will order,

28 x 8

= 224 kg.

**Rough Workspace**

Example #4

Sanjay, Suraj and Sanam prepared for running around a circular field. they complete one round in 12 seconds, 8 seconds, 20 seconds respectively. Find how much time will require to meet them again at the starting position?

- 48 seconds
- 2 minutes
- 4 minutes
- 9 minutes

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**Answer:**Option (B)

**How to Solve**

L.C.M of 12, 8, 20 is 120 seconds.

So, required time is 2 minutes.

**Rough Workspace**

Example #5

To filled a tank it is required 119 liter of petrol, then how many tanks would be required to fill 2142 liter of petrol?

- 12
- 14
- 16
- 18

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**Answer:**Option (D)

**How to Solve**

2142 / 119 = 18

**Rough Workspace**

Example #6

? / 2025 = 81 / ?

What number should places in the question mark?

- 405
- 427
- 449
- 471

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**Answer:**Option (A)

**How to Solve**

? / 2025 = 81 / ?

? x ? = 2025 x 81

?

^{2}= 45

^{2}x 9

^{2}

? = 45 x 9

? = 405

**Rough Workspace**

Example #7

If (12)^{3} is subtracted from the square of a number and answer is 2497. What would be the number?

- 53
- 65
- 71
- 87

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**Answer:**Option (B)

**How to Solve**

Let, the number is X.

X

^{2}– 12

^{3}= 2497

X

^{2}= 2497 + 1728

X = √4225

X = 65

**Rough Workspace**

Example #8

A cable is reap in 40 pieces each of 9 meter. If length of each pieces is increased by 3 meter, how many pieces will be formed?

- 20
- 25
- 30
- 34

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**Answer:**Option (C)

**How to Solve**

Total length of the cable is,

40 x 9

= 360 meter.

If length of each pieces is increased by 3 meter, i.e, ( 9 + 3 ) = 12 meter,

Then total pieces will be,

360 / 12

= 30 pieces.

**Rough Workspace**

Example #9

The difference between 68% of a number and 36% of the same number is 4780. What would be the 16% of that number?

- 2022
- 2148
- 2246
- 2390

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**Answer:**Option (D)

**How to Solve**

68% – 36% = 4780

32% = 4780

16% = 4780 x 16 / 32

16% = 2390.

**Rough Workspace**

Example #10

A shop owner sold 15 kg of apple per day. How many kg of apple will he sale in 5 weeks?

- 525 kg
- 555 kg
- 575 kg
- 595 kg

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**Answer:**Option (A)

**How to Solve**

5 weeks = ( 5 x 7 ) = 35 days.

So, he will sale,

35 x 15

= 525 kg.

**Rough Workspace**

Example #11

If the difference of a number and it’s 1/8 part is 35, then what would be the number?

- 32
- 36
- 40
- 44

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**Answer:**Option (C)

**How to Solve**

Let the number be X.

X – X / 8 = 35

7X / 8 = 35

7X = 280

X = 40

**Rough Workspace**

Example #12

A box has 18 dozen of candles. If there are 37 such boxes, then how many candles are there in all the boxes together?

- 6745 candles
- 7992 candles
- 8236 candles
- 8643 candles

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**Answer:**Option (B)

**How to Solve**

18 dozen of candles means,

18 x 12

= 216.

One box contain 216 candles.

So, 37 box will contain,

216 x 37

= 7992 candles.

**Rough Workspace**

### Problem on Numbers

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