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# Geometry Formula

## Geometry Formula

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Square Properties : P = Perimeter
A = Area
S = Side
d = diameter

P = 4 x s
A = S2
d = a x √2

### Rectangle Properties : P = Perimeter
A = Area
d = diameter

P = 2 x ( a + b )
A = a x b
d = √a2 + b2

### Triangle Properties : P = Perimeter
A = Area

P = a + b + c
A = b x h / 2

A = √s(s-a)(s-b)(s-c);

s = a + b + c / 2 = p / 2.

α + β + γ = 180o

### Circle Properties : P = Perimeter
A = Area

P = 2πr

A = πr2

π = 3.14

### Parallelogram Properties : P = (a + b) x 2
P = 2a + 2b

A = bh = ab sin α

### Circular Sector Properties : L = πr = θ / 180 0

A = πr2 θ/360 0

### Pythagorean Theorem : a2 + b2 =  c2

c = √a2 + √b2

### Circular Ring Properties : A = π (R2 – r2)

### Sphere Properties : S = 4πr2

V = 4/3πr3

### Trapezoid Properties : P = a + b  + c + d

A = h x  a + b / 2

### Rectangular Box Properties : A =  2ab + 2ac + 2bc

V = abc

### Right Circular Cone : A = πr2 + πrs

S = √r2 +√h2

V = 1 x πr2 h / 3

### Cube Properties : A = 6l2

V = l3

### Cylinder Properties : A = 2πr( r + h)

V = πr2 h

### Frustum of a Cone Properties : V = 1 x πh (r2 + rR + R2) / 3

If You Have any question regarding this topic then please do comment on below section. You can also send us message on facebook.

1. kishan rajoriya says:

y =2x ,y=-2x and y=6 se paribadh tribhugh ka area kya hoga please give me this question answer

2. Ishan says:

Volume of sphere should be 4/3*pi*r^3..

3. 4. 5. 