Mixture and Alligation shortcut tricks are very important thing to know for your exams. Time takes a huge part in competitive exams. If you know time management then everything will be easier for you. Most of us skip that part. Here in this page we give few examples on Mixture and Alligation shortcut tricks. All tricks on mixture and alligation are provided here. Visitors please read carefully all shortcut examples. These examples will help you to understand shortcut tricks on Mixture and Alligation.
Before doing anything we recommend you to do a math practice set. Write down twenty math problems related to this topic on a page. Do first ten maths using basic formula of this math topic. You also need to keep track of timing. After finish write down total time taken by you to solve those ten maths. Now read our examples on mixture and alligation shortcut tricks and practice few questions. After doing this go back to the remaining ten questions and solve those using shortcut methods. Again keep track of Timing. You will surely see the improvement in your timing this time. But this is not all you need. If you need to improve your timing more then you need to practice more.
Math section in a competitive exam is the most important part of the exam. It doesn’t mean that other topics are not so important. But if you need a good score in exam then you have to score good in maths. Only practice and practice can give you a good score. All you need to do is to do math problems correctly within time, and only shortcut tricks can give you that success. But it doesn’t mean that without using shortcut tricks you can’t do any math problems. You may have that potential that you may do maths within time without using any shortcut tricks. But other peoples may not do the same. For those we prepared this mixture and alligation shortcut tricks. We try our level best to put together all types of shortcut methods here. But we may miss few of them. If you know anything else rather than this please do share with us. Your help will help others.
Mixture and Alligation Examples Here in this Mixture and Alligation Methods and some important formula which need to understand through examples that’s are given in exams. we provide u some example 1 based on mixture and alligation. This is the basic theory of Mixture and Alligation which is applied in question to obtain answers here Mixture and Alligation Methods of example in different form of examples.
In maths exam papers there are two or three question are given from this chapter. This type of problem are given in Quantitative Aptitude which is a very essential paper in banking exam. Under below given some more example for your better practice.
Example #1 In what ratio must a shopkeeper mix two type of rice worth Rs.50/- per kg and Rs.58/- per kg so that by selling the mixture at Rs.58.30/- per kg and he may gain 10% ?
3 : 2
5 : 2
4 : 3
5 : 3
Show AnswerShow How to SolveOpen Rough Workspace
Answer: Option (D)
How to Solve Selling price of 1 kg rice of the mixture = Rs.58.30/-. Gain = 10%.
Cost price of 1 kg of the mixture = 100 x 58.30 / 110 = Rs.53/-.
By the rule of alligation: C.P.M.1 = ( Cost price of First rice ) = Rs.50/- C.P.M.2 = ( Cost price of Second rice ) = Rs.58/- M.P. = ( Mean price of both Material ) = Rs.53.00/-
So, the required ratio of both materials is 5 : 3.
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Example #2 In what proportion some sugar of Rs.3.25/- per kg be mixed with another type of sugar of Rs.3.80/- per kg, so that the mixture would be the worth of Rs.3.50/- per kg?
5 : 6
6 : 5
7 : 8
8 : 9
Show AnswerShow How to SolveOpen Rough Workspace
Answer: Option (B)
How to Solve By the rule of alligation: Quantity of cheaper / Quantity of dearer = CP of dearer – Mean price / Mean price – CP of cheaper Quantity of cheaper / Quantity of dearer = 380 – 350 / 350 – 325 Quantity of cheaper / Quantity of dearer = 30 / 25 = 6 / 5
So, They must be mixed in the ratio of 6 : 5.
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Example #3 In a what ratio wheat of Rs.12.30/- per kg be mixed with wheat of Rs.18.30/- per kg, so that the mixture would be worth of Rs.15/- per kg?
9 : 10
10 : 9
9 : 11
11 : 9
Show AnswerShow How to SolveOpen Rough Workspace
Answer: Option (D)
How to Solve Here we apply alligation rule that is ( Cheaper quantity ) : ( Dearer quantity ) = ( d – m ) : ( m – c ).
C.P.M.1 = ( Cost price of First material ) = 12.30 = 1230 C.P.M.2 = ( Cost price of Second material ) = 18.30 = 1830 M.P = ( Mean price of both Material ) = 1500
So, the required ratio of both materials is 11 : 9.
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Example #4 In a mixture of water and milk there was 18 liters of water of 96 paise per liter. If the price of the milk be Rs.1.12 per liter. Find how much milk is present in that mixture?
100 Liters
108 Liters
118 Liters
126 Liters
Show AnswerShow How to SolveOpen Rough Workspace
Answer: Option (B)
How to Solve The mean value is 96 paise and price of water is 0 paise. Using alligation rule the ratio of milk and water is 6 : 1. So, the quantity of milk is present in this mixture is, ( 6 x 18 ) = 108 liters.
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Example #5 In what ratio must water be mixed with milk that would worth Rs.18/- per liter to obtain a mixture worth Rs.12/- per liter?
1 : 2
2 : 3
3 : 4
4 : 5
Show AnswerShow How to SolveOpen Rough Workspace
Answer: Option (A)
How to Solve Ratio of water and milk is 6 : 12 = 1 : 2.
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Example #6 In how many kilogram of tea worth Rs.9/- per kg mixed with 36 kg of tea worth Rs.6/- per kg, so that it’s gain is 20% and that mixture is selling at the price of Rs.8.40/- per kg?
14 kg
16 kg
18 kg
20 kg
Show AnswerShow How to SolveOpen Rough Workspace
Answer: Option (C)
How to Solve Selling price of 1 kg of mixture = Rs.8.40. Gain = 20%.
So, cost price of 1 kg of mixture = 100 x 8.40 / 120 = Rs.7/-.
Using alligation rule Ratio of quantities of 1st and 2nd = 1 : 2 So, 1 : 2 = X : 36 X = 36 x 1 / 2 X = 18 kg.
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Example #7 A goldsmith has two qualities of gold one of 14 carats and another of 17 carats purity. In what proportion should he mix both to make an ornament of 16 carats purity?
1 : 2
2 : 1
3 : 2
2 : 3
Show AnswerShow How to SolveOpen Rough Workspace
Answer: Option (A)
How to Solve By using the formula of alligation Quantity of cheaper / Quantity of dearer = CP of dearer – Mean price / Mean price – CP of cheaper = 17 – 16 / 16 – 14 = 1 / 2.
So, They must be mixed in the ratio of 1 : 2.
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Example #8 A grocery has 600 kg of rice. He sells a part from it at a 12% profit and the rest of at 24% profit. He gains 16% on the entire. Find quantity sold at 24% profit.
175 kg
200 kg
220 kg
245 kg
Show AnswerShow How to SolveOpen Rough Workspace
Answer: Option (B)
How to Solve By the rule of alligation Profit on First part = 12% Profit on second part = 24% Profit on Mean = 16% So, ( profit on First part – Profit on Mean ) : ( Profit on Second part – Profit on Mean ) = ( 12% – 16% ) : ( 24% – 16% ) = 8 : 4 = 2 : 1.
So, the ratio of First and Second parts, = 8 : 4 = 2 : 1.
Quantity sold of second part, = ( 1 x 600 / 3 ) = 200 kg.
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Example #9 Find the ratio in which fresh sugar of Rs.8.40/- per kg be mixed with sugar of Rs.4.80/- per kg to produce a mixture worth Rs.6.80/- per kg.
3 : 4
4 : 3
4 : 5
5 : 4
Show AnswerShow How to SolveOpen Rough Workspace
Answer: Option (D)
How to Solve Using rule of alligation: So, the required ratio is, = 200 : 160 = 5 : 4.
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Example #10 Find in what ratio must a grocer mix two type of tea of Rs.20/- and Rs.22/- per kg, so that the mixture would be worth of Rs.18.50/- kg?
3 : 7
7 : 3
5 : 7
7 : 5
Show AnswerShow How to SolveOpen Rough Workspace
Answer: Option (B)
How to Solve Using the rule of alligation
So, the required rate is, = 350 : 150 = 35 : 15 = 7 : 3.
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Example #11 A dishonest shopkeeper professes to sell his milk at the cost price. But he mixed it with water and because of that he gains 20%. Find the percentage of water in the mixture is.
12.98%
14.45%
16.67%
18.35%
Show AnswerShow How to SolveOpen Rough Workspace
Answer: Option (C)
How to Solve Let, Cost price of 1 liter milk is Rs.1/-. So, sell price of 1 liter of mixture is Rs.1/-, and he Gain = 20%. Cost Price of 1 liter mixture is, = 100 x 1 / 120 = 5 / 6.
Using alligation rule: Ratio of milk to water is, 5 / 6 : 1 / 6 = 5 : 1.
So, the percentage of water in the mixture is, = 1 x 100 / 6 = 16.67%.
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Example #12 Two vessels P and Q has contain milk and water in the ratio of 5 : 2 and 7 : 6 respectively. What would be the ratio in which these mixture now be mixed and obtain a new mixture in a vessels R contain milk and water in the ratio of 8 : 5 ?
5 : 7
7 : 8
9 : 7
7 : 9
Show AnswerShow How to SolveOpen Rough Workspace
Answer: Option (D)
How to Solve Let, the Cost price of milk be Rs.1/- per liters. Milk in 1 liter mixture of vessels P = 5 / 7 liter, Cost price of 1 liter mixture in vessels P = Rs. 5 / 7.
Milk in 1 liter mixture of vessels Q = 7 / 13 liter. Cost price of 1 liter mixture in vessels Q = Rs. 7 / 13.
Milk in 1 liter mixture of R = 8 / 13 liter. Mean price = Rs. 8 / 13.
Using alligation rule:
So, the required ratio is, = 1 / 13 : 9 / 91 = 7 : 9.
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Few examples of Mixture and Alligation with Shortcut Tricks
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18 comments
nitish says:
Thank u so much it has really turned things a bit easy way
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Thank u so much it has really turned things a bit easy way
yo man!
this is really best … can easily revise things .. logically formulated and wonderfully explained..
Well explained. Thank you.
Plz explain que no 12
thanks well explained
Very Very awesome and quite useful sir.
tnx
Awesome explanations. Really helpful for quick reference.
thanks, keep visiting
Thanks its good method for competitive exams
Super
Nice explanation…
very nice
Good collection of questions. Explained really well.
Keep posting more tricks
nice explanation
Well explained.
super
Disclaimer:
All contents of this website is fully owned by Math-Shortcut-Tricks.com. Any means of republish its content is strictly prohibited. We at Math-Shortcut-Tricks.com are always try to put accurate data, but few pages of the site may contain some incorrect data in it. We do not assume any liability or responsibility for any errors or mistakes in those pages. Visitors are requested to check correctness of a page by their own.