Mixture and Alligation Methods shortcut tricks are very important thing to know for your exams. Time is the main factor in competitive exams. If you know time management then everything will be easier for you. Most of us miss that part. Few examples on mixture and alligation shortcuts
Before starting anything just do a math practice set. Choose any twenty math problems and write it down on a page. Using basic math formula do first ten maths of that page. You also need to keep track of timing. Write down the time taken by you to solve those questions. Now go through our page for mixture and alligation shortcut trick. After this do remaining ten questions and apply shortcut formula on those math problems. Again keep track of the time. You will surely see the improvement in your timing this time. But this is not all you need. You need more practice to improve your timing more.
Math section in a competitive exam is the most important part of the exam. That doesn’t mean that other sections are not so important. But only math portion can leads you to a good score. You can get good score only by practicing more and more. You should do your math problems within time with correctness, and only shortcut tricks can give you that success. But it doesn’t mean that you can’t do math problems without using any shortcut tricks. You may have that potential that you may do maths within time without using any shortcut tricks.
But, other peoples may not do the same. So Mixture and Alligation shortcut tricks here for those people. We try our level best to put together all types of shortcut methods here. But we may miss few of them. If you know anything else rather than this please do share with us. Your little help will help others.
Now we will discuss some basic ideas of Mixture and Alligation methods. On the basis of these ideas we will learn trick and tips of shortcut mixture and alligation methods. If you think that how to solve mixture and alligation methods questions using mixture and alligation methods shortcut tricks, then further studies will help you to do so.
Here in this chapter using Alligation rule we find the average value of mixture when the price of two or more ingredients which mixed together and some important formula which need to understand through examples that are given in exams. We provide you some examples on mixture and alligation shortcut tricks. This is the basic theory of Mixture and Alligation which is applied in question to obtain answers here. Mixture and Alligation Methods of example in different form of examples.
Anything we learn in our school days was basics and that is well enough for passing our school exams. Now the time has come to learn for our competitive exams. For this we need our basics but also we have to learn something new. That’s where shortcut tricks are comes into action. In maths exam papers there are two or three question are given from this chapter.
This type of problem are given in Quantitative Aptitude which is a very essential paper in banking exam. Under below given some more example for your better practice in Mixture and Alligation shortcut tricks or Mixture and Alligation shortcut or Mixture and Alligation tricks or Mixture and Alligation formula or Mixture and Alligation problems.
This is the rule that enables us to find the ratio in which two or more ingredients or material at the given price must be mixed to produce a mixture of a desired price.
Cost price of an unit quantity of the mixture is call the mean price.
If Two ingredients are mixed in a ratio, So
( Quantity of cheaper / Quantity of dearer ) = ( C.P of dearer ) – ( Mean price ) /( Mean price ) – (C.P. of cheaper )
We present it under as
C.P.M.1 = Cost Price of First Materiel in a Mixture.
C.P.M.2 = Cost Price of Second Materiel in a Mixture.
C.P.M.3 = Cost Price of Mixture.
So,
C.P.M.1 : C.P.M.2 = ( C.P.M.1 – C.P.M.3 ) : ( C.P.M.2 – C.P.M.3 ).
OR,
(Cheaper quantity ) : ( Dearer quantity ) = ( d – m ) : ( m – c ).
m = mean price.
d = C.P of dearer.
c = C.P of cheaper.
Here is another important formula which is,
Consider a container contain X units.
From which we are taken out Y units and replace it by water.
After n operations, the quantity of pure liquid will be
[ X x ( 1 – Y / X )n] units.
So, here we provide few tricks on Mixture and Alligation. So, Please visit this page to get updates on more Math Shortcut Tricks. You can also like our facebook page to get updates.
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Nice examples
these are the easy questions..please add few difficult question as the competition level is increased.
please add some more tricks and examples
The explanation u gave here is quite simple and most important of all u defined those things which i was very much puzzled about. Thanks a lot for your effort. 🙂
There are two vessels A and B in which the ratio of milk and water are as 5:2 and 8:7 respectively. Two gallons are drawn from vessel A and 3 gallons are drawn from vessel B, and are mixed in another empty vessel. what is the ratio of milk and water in it?
sir i need the explanation and shortcut method for this problem.
106:69, if it is right let me know , I will help you solving that easy.
Plse help to find allegation method
34:25..??
If A is 5:2 B is 8: 7 .if we add 5+2=7 and 8+7=15 if both answer differ then cross multiple it.that is 5 x 15 :2 x 15 and 8 x 7: 7 x 7 then we get answer as 75:30 and 56:49.now u add 75+30=105 and 56+ 49=105 as answer.if u get equally then apply 2:3 as 75 x 2: 30x 2and 56 x 3 : 49 x 3.now u get answer as 318: 207 then once again divide u get as 106:69.
How to solve this sum
The cost of 30 purses and 20 walllets is 8500 what is the cost of 117 purses and 78 wallets
divide by 10 and multiply by 2
30:20==8500
Divide by 10 both side
3:2. =850
Multiplied both side by 39
117:78= 850×39
=33150
devide by 10, multiply by 39
Ans is 117p+78w=33150
33150
Let me know if its correct or not
30 P, 20 W =8500
10 (3P,2W)=8500
3P,2W=850
39(3P,2W)=850*39
answer is 33150= 117P,78W
why should we multiply with 39 there
What is that ‘n’ in last formula of mixtures. I didn’t understand.
n is number operation performed
What about the problem having 3 components mixed together? How can we use alligation method then?
a bottle is full of dettol. one third of it is tajen out and equal amount of water is poured. this operation is repeated four times. find the final ratio of dettol and water?
16:65
pls more formula examples uesd
30P+20W= 8500
117P+78W=3.9(30P+20W=8500)
SO,
3.9(8500)=33,150/-
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