## Time and Work Math Example 2

Shortcut Tricks are very important things in competitive exam. Time takes a huge part in competitive exams. If you know time management then everything will be easier for you. Most of us miss that part. Here in this page we give few examples on Time and Work shortcut tricks. We try to provide all types of shortcut tricks on time and work here. Visitors are requested to carefully read all shortcut examples. These Time and Work Math Example will help you to better understand shortcut tricks on time and work.

First of all do a practice set on math of any exam. Write down twenty math problems related to this topic on a page. Solve first ten math problems according to basic math formula. You also need to keep track of the time. After finish write down total time taken by you to solve those ten maths. Now read our examples on time and work shortcut tricks and practice few questions. After finishing this do remaining questions using Time and Work shortcut tricks. Again keep track of timing. This time you will surely see improvement in your timing. But this is not all you need. You need more practice to improve your timing more.

### Few things to Remember

We all know that the most important thing in competitive exams is Mathematics. It doesn’t mean that other topics are not so important. But only math portion can leads you to a good score. You can get good score only by practicing more and more. The only thing you need to do is to do your math problems correctly and within time, and you can do this only by using shortcut tricks. Again it does not mean that you can’t do maths without using shortcut tricks. You may do math problems within time without using any shortcut tricks. You may have that potential.

But, so many people can’t do this. For those we prepared this time and work shortcut tricks. We try our level best to put together all types of shortcut methods here. But if you see any tricks are missing from the list then please inform us. Your little help will help so many needy.

### Time and Work Math Example 2

Some important facts are needed for Time and Work Example Problems . Here is some Time and Work Math Examples of this chapter related are given. Such that a person do a piece of work which has to be require more time to complete why because capacity is limited to that person but two or more person do the same piece of work which require less time and effort .

Another type is **two person work a piece of work in same time and third one join this work and find out all persons together work to complete**, So here is some example 2 of Time and work Math and Time and work shortcut tricks related which help you better study for job preparation.

This type of problem are given in Quantitative Aptitude which is a very essential paper in banking exam . Under below given some more example for your better practice.

### Example #1 – Time and Work Math Example

P, Q and R can complete a piece of work in 8, 12 and 24 days respectively. How many days will required to complete the same work if they work together.

- 4 Days
- 6 Days
- 10 Days
- 16 Days

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (A)

**How to Solve**

P’s 1 day work = 1 / 8

Q’s 1 day work = 1 / 12

R’s 1 day work = 1 / 24

So, together they need,

(1 / 8) + (1 / 12) + (1 / 24)

or, (3 + 2 + 1) / 24

or, 1 / 4

= 4 days.

So, they need 4 days to complete the work if they work together.

**Rough Workspace**

### Example #2 – Time and Work Math Example

4 boys and 6 girls can complete a piece of work in 8 days while 3 boys and 7 girls can complete the same piece of work in 10 days. Find the required days needed for 10 girl to complete that work.

- 18 Days
- 25 Days
- 40 Days
- 50 Days

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (C)

**How to Solve**

Let, 1 boy’s 1 day’s work = X.

Let, 1 girl’s 1 day’s work = Y.

Then, 4X + 6Y = 1 / 8

And, 3X + 7Y = 1 / 10

By solving of two equations,

We get Y = 1 / 400 and X = 11 / 400.

So, 1 girl’s 1 day’s work = 1 / 400.

Then 10 girl’s 1 day’s work = (1 x 10 / 400) = 1/40.

So, 10 girl will complete the work in 40 days.

**Rough Workspace**

### Example #3 – Time and Work Math Example

John painted a wall in 3 days of 12 hours each and Paul can do it in 3 days of 8 hours each. How long will they take to do it, working together 12 / 5 hours a day?

- 4 Days
- 6 Days
- 7 Days
- 12 Days

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (B)

**How to Solve**

John finished the work in ( 3 x 12 ) = 36 hours.

Paul finished the work in ( 3 x 8 ) = 24 hours.

So, John’s 1 hour work = 1 / 36

And, Paul’s 1 hour work = 1 / 24

Together their 1 hour work

= ( 1 / 36 ) + ( 1 / 24 )

= 5 / 72 hours.

So, both finished the work in 72 / 5 hours.

Or, ( 72 / 5 ) X ( 5 / 12) = 6 days.

So, they need 6 days to complete the work if they work together.

**Rough Workspace**

### Example #4 – Time and Work Math Example

Ram and Shyam can do a piece of work in 30 days. They work together in 20 days and then Shyam left. After another 20 days Ram finish the remaining work. In how many days Ram can alone finish the work?

- 35 Days
- 45 Days
- 50 Days
- 60 Days

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (D)

**How to Solve**

Ram and Shyam together 1 day work is 1 / 30.

So, their 20 days work

= ( 1 x 20 / 30 )

= 2 / 3.

Remaining work

= 1 – ( 2 / 3 )

= 1 /3.

Now, 1 / 3 work done by Ram in 20 days.

So, the whole work done by Ram is

20 / (1 / 3)

or, 20 x 3

= 60 days.

**Rough Workspace**

### Example #5 – Time and Work Math Example

30 children can complete a piece of work in 50 days. Find how many days will required for 15 children to complete the same piece work?

- 100 Days
- 120 Days
- 125 Days
- 150 Days

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (A)

**How to Solve**

We use

( Children x Working days ) = ( Children x Working days )

30 x 50 = 15 x ?

1500 = 15 x ?

? = 100 days.

**Rough Workspace**

### Example #6

P and Q can do a piece of work in 45 days and 40 days respectively. They began the work together. But P left after some time and Q finished the remaining work in 23 days. After how many days did P leave?

- 5 Days
- 7 Days
- 9 Days
- 11 Days

Show Answer Show How to Solve Show Shortcut Tricks Open Rough Workspace

**Answer:**Option (C)

**How to Solve**

Q works alone for 23 days.

So, Work done by Q in 23 days = 23 / 40 work.

So, P + Q do together ( 1 – 23 / 40 ) = 17 / 40.

Then , P + Q do this work in 1 day ( 40 x 45 / 40 + 45 ) = 40 x 45 / 85 days.

So, P + Q together do the work in

= ( 40 x 45 / 85 ) x 17 / 40

= 9 days.

**Shortcut Tricks**

We can ignore middle steps then perform direct formula

40 x 45 / 40+ 45 ( 40 – 23 / 40 )

= 9 days.

**Rough Workspace**

### Example #7

30 labor can complete a piece of work in 32 days. In how many days 15 labor can complete the same work?

- 55 Days
- 64 Days
- 72 Days
- 84 Days

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (B)

**How to Solve**

We use

Labor x Working days = Labor x Working days

30 x 32 = 15 x ?

960 / 15 = ?

? = 64.

So, 15 labor can complete the same work in 64 days.

**Rough Workspace**

### Example #8

12 men can complete a construction work in 28 hours. In how many hours would be 24 men complete that construction work?

- 14 Hours
- 16 Hours
- 20 Hours
- 22 Hours

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (A)

**How to Solve**

12 men can complete a construction work in 28 hours.

12 x 28 = 24 x ?

? = 14 hours

**Rough Workspace**

### Example #9

P and Q can complete a work in 15 days and 10 days respectively. They began doing the work together. But, after 2 days Q had to leave and P alone complete the remaining work. So, in how many days the whole work was completed?

- 7 Days
- 10 Days
- 12 Days
- 15 Days

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (C)

**How to Solve**

(P + Q)’s 1 days work = ( 1 / 15 ) + ( 1 / 10 )

= 1 / 6.

So, work done by P and Q in 2 days = ( 1/6 x 2)

= 1 / 3.

Then, remaining work is (1 – 1/ 3)

= 2 / 3.

Now, P’s 1 day of work is 1 / 15.

So, remaining 2/3 work will be done by P in (2/3) / (1/15)

or, (2/3) X 15

= 10 days.

Hence, total time taken to finished the work is (10 + 2) = 12 days.

**Rough Workspace**

### Few Time and Work math example with Shortcut Tricks

- Time and work – Examples 1
- Examples of Time and work 3
- Time and Work – Examples 4
- << Go back to Time and Work main page

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If you have any question regarding this Time and Work Math example, then please do comment on below section. You can also send us message on facebook.

this site was really very good…

VERY HELPFULL THANK U

A and B together can do a piece of work in 5 hours,A and C together can do the same piece of in 4 hours,, B and C together can do the same work in 7/2 hours. How many hours A can alone do the same work ?

y 40 x 45/45+40

A+B= 1/5,B+C=2/7,C+A=1/4

2(A+B+C)=1/5+2/7+1/4

=28+40+35 /140

=103/140

A+B+C= 103/280

A alone can do same work = A+B+C – B+C

= 103/280 – 2/7

=103 – 80 / 280

=23/280 days and in hours 280/23 can A alone do the same work…….

A and B both complete works in 16 days and B and C complete works in 24 days….if A is working 3 more time(3 guna) than C. Than how many days will take A,B and C for this work?? Plz reply a shortrick for this question

i didnt undersatnd the 4th example can u pls elaborate it again

First step is here p given. That is Q works alone for 23 days and proceed.

4 men and 6 women can complete a work in 8days, while 3 men and 7 women can complete it in 10 days.in how many days will 10 women complete it.

take look this example Let 1 boy’s 1 day’s work = x.

Let 1 girl’s 1 day’s work = y.

Then, 4x + 6y = 1 / 8

3x + 7y = 1 / 10

by solving of two equations,

we get y = 1 / 400 and x = 11 / 400

So, 1 girl’s 1 day’s work = 1 / 400.

Then 10 girl’s 1 day’s work = (1 x 10 / 400) = 1 / 40.

So 10 girl will complete the work in 40 days.

how can we gaet y=1/400 after solving the two equations . i am getting y=1/40 ..?

I couldn’t understand this step. Please explain.

Then 10 girl’s 1 day’s work = (1 x 10 / 400) = 1 / 40.

I need best math book for bank exm… and new tricks

Can u suggest book name or publishers name

A can do tapiece of work in 4 hours,B&C can do the same work in 3 hours.A&C can do the same work in 2 hours.how long can B alone take to do the same work?

A+(B+C)-(A+C) = B

1/4 + 1/3 -1/2. = 1/12

B alone do in 12 days

Really wonderful and appreciable site…All my concepts are clear…Thanku

hi can anyone help me with example 6.

it says Q alone works for 23 days

but the ans states P alone works for 23 days

P & Q CAN DO A WORK IN 45 AND 40 DAYS RESPECTIVELY,THEY BEGAN THE WORK TOGETHER, BUT P LEFT AFTER SOME TIME & Q FINISHED THE REMAINING WORK IN 23 DAYS .AFTER HOW MANY DAYS DIS P LEAVE ??

PLZ EXPLAIN.

can anyone explain the formula which s used in the 6th sum

Hi…very useful tips for to take a steps in clear the bank exams…thank you for your guideness…

yeah its good…..!!!!!!!!!

Ram and shyam can complete a piece of work in 8 days.if ram worked for 6 days and shyam completed the remining work in 10 days in how many days can shyam alone complete the work?

Sir any book written by you .pls suggest us thnk u

Sir how to apply direct formula