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## Pipe and Cistern Methods shortcut tricks

Shortcut tricks on Pipe and Cistern Methods are one of the most important topics in exams. Time is the main factor in competitive exams. If you manage your time then you can do well in those exams. Most of us skip that part. Here in this page we give few examples on **Pipe and Cistern shortcut tricks**

. These shortcut tricks cover all sorts of tricks on Pipe and Cistern. Visitors are requested to carefully read all shortcut examples. You can understand shortcut tricks on Pipe and Cistern by these examples.

Before starting anything just do a math practice set. Write down twenty math problems related to this topic on a page. Do first ten maths using basic formula of this math topic. You also need to keep track of Timing. After finish write down total time taken by you to solve those ten maths. Now go through our page for pipe and cistern shortcut trick. After finishing this do remaining questions using Pipe and Cistern shortcut tricks. Again keep track of the time. The timing will be surely improved this time. But this is not enough. You need to practice more to improve your timing more.

### Few Important things to Remember

We all know that the most important thing in competitive exams is Mathematics. That doesn’t mean that other topics are less important. But only math portion can leads you to a good score. A good score comes with practice and practice. The only thing you need to do is to do your math problems correctly and within time, and this can be achieved only by using shortcut tricks. But it doesn’t mean that you can’t do math problems without using any shortcut tricks. You may have that potential to do maths within time without using any shortcut tricks. But other peoples may not do the same. Here we prepared pipe and cistern shortcut tricks for those people. We try our level best to put together all types of shortcut methods here. But it possible we miss any. We appreciate if you share that with us. Your help will help others.

### Pipe and Cistern Methods

Now we will discuss some basic ideas of **Pipe and Cistern Methods**. On the basis of these ideas we will learn trick and tips of shortcut pipe and cistern methods. If you think that **how to solve pipe and cistern methods questions using pipe and cistern methods shortcut tricks**, then further studies will help you to do so.

Here is some Pipe and Cistern methods we discuss with examples. This type of problem are given in Quantitative Aptitude which is a very essential paper in banking exam. Under below given some more example for your better practice.

Anything we learn in our school days was basics and that is well enough for passing our school exams. Now the time has come to learn for our competitive exams. For this we need our basics but also we have to learn something new. That’s where shortcut tricks are comes into action.

### What is Inlet?

**Inlet:** A Pipe is linked with plastic tank and it fills with water is called as Inlet. A pipe can fill a tank with water at this time the nature of pipe is plus.

### What is Outlet?

**Outlet:** A Pipe linked with tank it vacant is called as an outlet. A pipe can vacant a tank means nature of pipe is minus.

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Help for these topics like pipe and cisterns and average and no system also

Twp pipes A& B fill a tank in 20 min & 30 mins respectively and pipe C empty the tank in 15 mins.if all pipes are opened successively then in what time tank will completely filled..??

According to formula..

-mnp/m×n+(-n×p)+(-p×m)

-20×30×15/20×30-30×15-15×20

=-9000/600-450-300

=-9000/600-150

=-9000/500

=18min.

60 minutes

It will not fill at any more..

60 minutes will be required to fill ups the tank.

1/20+1/30-1/15

=>1/60

60mints

Vol. =lcm(20,30,15)=60

A can fill/min.=3unit

B can fill /min=2unit

Total fill/min=5unit

C can empty the tank/min=4unit(60/44

So total fill /min=5-4=1unit

So total time taken to fill the tank=60 min or 1h

(1/20+1/30)-1/15=1/60

60min

take LCM = 3+2-4/60 = 1/60 ONE MIN , 60 MIN IS REQUIRED TO FILL THE TANK.

Let Capacity =60L

Rate of A=3L/M

Rate of B= 2L/M

Rate of C=4L/M

Net inflow=1L/M

For 60L it’s 60M assuming all pipes are open simultaneously

1/20+1/30-1/15

LCM of 20,30,15 is60

3+2-4/60=x

X=60minutes

X= 1 hour

1/20+1/30-1/15 = 1/60

Hence 60/1 mins.

60 mins

60 mins

60 mins

60mins will be required to fill up the tank or 1hour

60

167 minutes

can u explain the same using lcm method

X=20,Y=30,Z=15

THIS IS FORMULA 1/X+1/Y-1/Z

IF WE USE LCM METHOD FORMULA WILL BE IN THIS FORM,

X*Y*Z/ Y*Z+Z*X-Y*X

=20*30*15/30*15+20*15-30*20

=9000/450+300-600

=9000/150

=900/15

=60 MINS

60 min is required to fill the tank