## Pipe Example 1

Shortcut Tricks are very important things in competitive exam. Competitive exams are all about time. If you know time management then everything will be easier for you. Most of us skip that part. We provide examples on Pipe shortcut tricks here in this page below. All tricks on pipe are provided here. Visitors please read carefully all shortcut examples. These examples will help you to understand shortcut tricks on Pipe.

Before doing anything we recommend you to do a math practice set. Write down twenty math problems related to this topic on a page. Do first ten maths using basic formula of this math topic. You also need to keep track of timing. After finish write down total time taken by you to solve those ten maths. Now go through our page for pipe shortcut trick. After finishing this do remaining questions using Pipe shortcut tricks. Again keep track of the time. This time you will surely see improvement in your timing. But this is not all you want. If you need to improve your timing more then you need to practice more.

We all know that the most important thing in competitive exams is Mathematics. It doesn’t mean that other topics are not so important. You can get a good score only if you get a good score in math section. Only practice and practice can give you a good score. You should do your math problems within time with correctness, and this can be achieved only by using shortcut tricks. But it doesn’t mean that you can’t do math problems without using any shortcut tricks. You may have that potential that you may do maths within time without using any shortcut tricks.

But, other peoples may not do the same. For those we prepared this pipe shortcut tricks. We try our level best to put together all types of shortcut methods here. But it possible we miss any. We appreciate if you share that with us. Your help will help others.

Pipe and Cistern Example 1

In pipe and cisterns when we calculate the pipe related examples we first check the nature that if the pipe is filled up by water or any liquid we clearly say and consider the pipe is plus and when the pipe is vacant we clearly say and consider it as negative, so here we again describe rule of pipe example and also some example is given. This type of problem are given in Quantitative Aptitude which is a very essential paper in banking exam.Under below given some more example for your better practice.

### Formulas of Pipe and Cistern

- If a pipe can fill a tank in X hours, then, part filled by 1 hours =
**1 / X**.

- If a pipe can vacant a tank in Y hours, then, part emptied in 1 hours =
**1 / Y**.

- If a pipe can fill a tank in X hours and another pipe can vacant the full tank in Y hours ( where X>Y ), then on opening both the pipes, the net part filled in 1 hours =
**(1 / X) – (1 / Y).**

- If a pipe can fill a tank in X hours and another pipe can empty the full tank in Y hours ( where Y>X ), then on opening both the pipes, the net part emptied in 1 hours =
**(1 / Y) – (1 / X).**

Example #1

A water reservoir can fill by a tap in 12 hours and a bottom tap can vacant that water reservoir in 18 hours. If the tap of a water reservoir fill and opened simultaneously, then what time will it takes to be filled.

- 30 Hours
- 36 Hours
- 40 Hours
- 44 Hours

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (B)

**How to Solve**

1 / 12 – 1 / 18

= 1 / 36

So, it will takes 36 hours to be filled the tank.

**Rough Workspace**

Example #2

Two pipes A and B can fill a water reservoir in 12 hours and 14 hours respectively. While a third pipe C empties the full water reservoir in 30 hours. If all the pipes A, B and C is operate simultaneously, how much time will take be filled the water reservoir?

- 8 Hours 12 Minutes
- 8 Hours 48 Minutes
- 9 Hours 18 Minutes
- 9 Hours 36 Minutes

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (A)

**How to Solve**

Net part filled by 1 hour

( 1 / 12 + 1 / 14 ) – 1 / 30

= 51 / 420.

The time taken will fill the water reservoir is 420 / 51 = 8 hr 12 minutes.

**Rough Workspace**

Example #3

Two pipes pipe 1 and pipe 2 can fill a water reservoir in 36 hours and 45 hours respectively. If both the pipes are opened simultaneously, how much time will be taken to fill the water reservoir?

- 10 Hours
- 14 Hours
- 18 Hours
- 20 Hours

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (D)

**How to Solve**

Here both pipes are filled so we can easily say it is a positive.

So, at first we calculate the portion it fill in 1 hour.

Pipe 1 + Pipe 2 together filled a water reservoir in 1 hour is

(1 / 36) + (1 / 45)

= 9 / 180

= 1 / 20

Hence, both the pipe, pipe 1 and pipe 2 will fill the water reservoir in 20 hours.

**Rough Workspace**

### Few examples of Pipe and Cistern with Shortcut Tricks

We provide few shortcut tricks on this topic. Please visit this page to get updates on more Math Shortcut Tricks. You can also like our facebook page to get updates.

If You Have any question regarding this topic then please do comment on below section. You can also send us message on facebook.

Pipe A can fill a tank in 20 min,Pipe B can empty a tank in 70 min, if both the pipes are open simultaneously than by what time the tank will be filled up.?

please do provide the answer with detailed explanation.

A filled the tank in 1/20 per mint

b empty the tank in 1/70 per mint

if both are opened simultaneously

so (1/20 -1/70)=(7-2)/140

=5/140 per hr

ans is 140/5 hrs =28 hrs take to fill the tank

greet

wrong.. how can u say hrs to fill the tank. in Q? he asked in min. stupid

in 1 min pipe A can fill:-1/20 part.

in 1 min pipeB can fill:-1/70part

if both the pipe are used for filling a tank then in 1min it can ill:-1/20+1/70 part of tank.

therefore both pipe can fill the the tank in 140/9 min.

in 1 min pipe A can fill:-1/20 part.

in 1 min pipeB can emptyl:-1/70part

if both the pipe are used for filling a tank then in 1min it can ill:-1/20-1/70 part of tank.

therefore both pipe can fill the the tank in 140/5 min.

A B

time 20 70 work LCM(20,70)= 140

effiency 7 2

since A is inlet take efficency as +ve and B as -ve (out let)

so 140work had to be done with 5efficency (7-2)

time taken = work /efficncy

=140/5

=28 min

20*70=1400

70-20=50

1400/50=28days answer..by short trick..

In 1hour tank filled =1/20

in 1 hour tank empty= 1/70

when both pipe operate then tank filled

=1/20-1/70Part

1hour=5/140part

1hour =1/28part

1 Part=28min in filled

In pipes and cistern method,what shortcuts you used?

lcm method

If two pipes can fill in 12 hr. One pipe fill 10 hr faster than other. How many hrs second pipe take to fill.

Tank capacity pls?

1/x be the time taken to fill (first pipe)

1/10+x be time taken by second pipe

So, 1/x + 1/x+10=1/12

=2x+10/x2 + 10x = 1/12

=x=20 hrs

wrong answer:

1/x + 1/(x+10) will form quadratic equation and than you have to solve that.

yeah its great!!!!!!!!!!!