Home > Math Shortcuts > Probability problem on Balls
Probability problem on Balls
Shortcut Tricks are very important things in competitive exam. Time is the main factor in competitive exams. If you know how to manage time then you will surely do great in your exam. Most of us miss that part. We provide examples on Probability problem on Balls shortcut tricks here in this page below. We try to provide all types of shortcut tricks on probability problem on balls here. Visitors are requested to carefully read all shortcut examples. These examples here will help you to better understand shortcut tricks on probability problem on balls.
Before doing anything we recommend you to do a math practice set. Then find out twenty math problems related to this topic and write those on a paper. Do first ten maths using basic formula of this math topic. You also need to keep track of the time. After solving all ten math questions write down total time taken by you to solve those questions. Now practice our shortcut tricks on probability problem on balls and read examples carefully. After this do remaining ten questions and apply shortcut formula on those math problems. Again keep track of timing. You will surely see the improvement in your timing this time. But this is not all you need. You need to practice more to improve your timing more.
Few Important things to Remember
We all know that the most important thing in competitive exams is Mathematics. That doesn’t mean that other sections are not so important. You can get a good score only if you get a good score in math section. Only practice and practice can give you a good score. All you need to do is to do math problems correctly within time, and you can do this only by using shortcut tricks. Again it does not mean that you can’t do maths without using shortcut tricks. You may have that potential that you may do maths within time without using any shortcut tricks.
But, other peoples may not do the same. So Probability problem on Balls shortcut tricks here for those people. We always try to put all shortcut methods of the given topic. But we may miss few of them. If you know anything else rather than this please do share with us. Your help will help others.
Here is some Probability on Balls Examples are given, Before going through this examples u should remember all probability formula and fact that are required here for solved the Example, Let do the Problems on Probability on Balls.
Example #1 – Probability problem on Balls
A bag contains 8 white balls and 6 black balls. If we taken out two random balls from that bag, then find the probability that they are of the same color?
- 22 / 91
- 28 / 91
- 34 / 91
- 43 / 91
Show Answer Show How to Solve Open Rough Workspace
Answer: Option (D)
How to Solve
Here S be the sample space.
So, n(S) = Number of ways of taken out balls of,
( 8 + 6 ) = 14
so, 14c2
or, ( 14 x 13 ) / ( 2 x 1 )
or, 182 / 2
therefore, 91.
E = Event of getting both balls of the same color.
Then, n(E) = Number of ways of drawing ( 2 balls out of 8 ) or ( 2 balls out of 6 )
so, ( 8C2 + 6C2 )
then, 8 x 7 / 2 x 1 + 6 x 5 / 2 x 1
then, 56 / 2 + 30 / 2
or, 28 + 15
therefore, 43.
P(E) = n(E) / n(S)
= 43 / 91.
A bag contain 4 red balls, 6 yellow balls. If 3 balls are drawn randomly, then what is the probability that they are of the same color?
Example 2: : plz correct answer….if u r correct then plz explain…
thank u….
What is the formula of probability
Could someone explain example 2 again?
Is this divya ramakrishna?
unaku vera velai ilaya
3balls with same color means,
3red or 3 yellow
(4C3 + 6C3 )/10C3,
( 4 + 20)/120 == 24/120 == 2/10 == 1/5
example no 3
how it become 8C1… plz explain it
i have the same question…..it should be 10C1.
Same doubt
n(E) = 15c3
n(S) = 5cz * 10c1
P(E) = n(E)/n(S)
ans:100/455 =20/91
the ans should be 20/91
Example:: It should be 12/55
Explain me how to do these sums …pls fast
Sir ball ke math ka example 3 samhjmain nahi aya hai…. Explain please
pls explain eg.3
how 8c1 came
1000 different balls in a bucket. One can select 250 balls at once. What is the probability of picking a ball at least once after 4 different picks?
To Vignesh : this is done wrong there should be 10 and its answer should be 5/11
Disclaimer:
All contents of this website is fully owned by Math-Shortcut-Tricks.com. Any means of republish its content is strictly prohibited. We at Math-Shortcut-Tricks.com are always try to put accurate data, but few pages of the site may contain some incorrect data in it. We do not assume any liability or responsibility for any errors or mistakes in those pages. Visitors are requested to check correctness of a page by their own.