## Find Principle or Sum based question

Shortcut tricks on Principle or Sum based question are one of the most important topics in exams. Competitive exams are all about time. If you manage your time then you can do well in those exams. Most of us skip that part. Few examples on principle or sum based shortcuts is given in this page below. We try to provide all types of shortcut tricks on principle or sum based here. We request all visitors to read all examples carefully. You can understand shortcut tricks on Principle or Sum based question by these examples.

First of all do a practice set on math of any exam. Choose any twenty math problems and write it down on a page. Solve first ten math problems according to basic math formula. You also need to keep track of the time. After finish write down total time taken by you to solve those ten maths. Now practice our shortcut tricks on principle or sum based and read examples carefully. After doing this go back to the remaining ten questions and solve those using shortcut methods. Again keep track of the time. You will surely see the improvement in your timing this time. But this is not enough. You need to practice more to improve your timing more.

### Few Important things to Remember

We all know that the most important thing in competitive exams is Mathematics. That doesn’t mean that other sections are not so important. But if you need a good score in exam then you have to score good in maths. A good score comes with practice and practice. You should do your math problems within time with correctness, and you can do this only by using shortcut tricks. Again it does not mean that you can’t do maths without using shortcut tricks. You may do math problems within time without using any shortcut tricks. You may have that potential. But so many other people may not do the same. Here we prepared principle or sum based shortcut tricks for those people. We always try to put all shortcut methods of the given topic. But if you see any tricks are missing from the list then please inform us. Your little help will help others.

When we borrow money from some one or we lent out some money for a some certain period is called the Principle or Sum. So here we find the Principle or Sum based question tricks.here is amount is given and time, and rate percent is given we just use formula and obtain the principle or sum. This type of problem are given in Quantitative Aptitude which is a very essential paper in banking exam. Under below given some more example for your better practice.

### Example #1

Suresh takes a sum of money for 2 years at Rs.885/- and for 3 years at Rs.985/-. Find the sum of money Suresh was taken.

- Rs.685/-
- Rs.785/-
- Rs.885/-
- Rs.985/-

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (B)

**How to Solve**

Simple interest in 1 year is = ( 985 – 885 ) = 100.

Simple interest in 2 years = 100 X 2 = 200.

So, Principal = ( 985 – 200 ) = Rs.785/-.

**Rough Workspace**

### Example #2

Samar takes a sum of money from Anup at simple interest of 25/2 per annum and amounts to Rs.3202.50/- after 6 years. Find the sum or principal taken by Samar from Anup.

- Rs.1830/-
- Rs.1940/-
- Rs.2060/-
- Rs.2280/-

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (A)

**How to Solve**

First we consider sum is X and Rate percent is 25/2 and Time is 6 years, So

SI = P x T x R / 100 = 3X / 4.

Amount = Sum + Simple Interest = X + 3X / 4 = 7X / 4

7X / 4 = 3202.50

So, X = 3202.50 X 4 / 7 = 1830.

Samar took a sum of Rs.1830/- from Anup.

**Rough Workspace**

### Example #3

What is the amount of Rs.16000/- at 5% per annum compound interest in 3 years?

- Rs.15883/-
- Rs.16887/-
- Rs.17322/-
- Rs.18522/-

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (D)

**How to Solve**

Time = 3

Rate = 5%

16000 x ( 105 / 100 ) = 16000 x 1157625 / 1000000

= 18522

So, the amount is Rs.18522/-.

**Rough Workspace**

### Example #4

John borrowed some money at the rate of 4% per annum for the first 3 years. At a rate of 7% per annum for the next 4 years. If he pays a total interest of Rs.12600/- at the end of 7 years, how much money did he borrow?

- Rs.25000/-
- Rs.28500/-
- Rs.31500/-
- Rs.35000/-

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (C)

**How to Solve**

Let, the sum borrowed by John is X

Then P = X

( P x T x R / 100 )

( X x 4 x 3 / 100) + ( X x 7 x 4 / 100) = 12600

( 3X / 25 + 7X / 25 ) = 12600

10X / 25 = 12600

X = 12600 x 25 / 10

X = 31500

So, John borrowed Rs.31500/-.

**Rough Workspace**

### More Shortcut tricks on Simple and Compound Interest

- Find Simple Interest based question
- Find the rate % based question
- Compound Interest shortcut tricks
- Find Compound Interest tricks
- Difference between CI and SI of Three Years question
- << Go back to SI and CI main page

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