Percentage shortcut tricks 5

Percentage short cut tricks 5

Shortcut Tricks are very important things in competitive exam. Competitive exams are all about time. If you know how to manage time then you will surely do great in your exam. Most of us miss that part. Here in this page we give few examples on percentage shortcut tricks. All tricks on percentage are provided here. Visitors are requested to carefully read all shortcut examples. You can understand shortcut tricks on percentage by these examples. Before starting anything just do a math practice set. Then find out twenty math problems related to this topic and write those on a paper. Do first ten maths using basic formula of this math topic. You also need to keep track of timing. After solving all ten math questions write down total time taken by you to solve those questions. Now go through our page for percentage shortcut trick. After doing this go back to the remaining ten questions and solve those using shortcut methods. Again keep track of Timing. This time you will surely see improvement in your timing. But this is not all you want. You need more practice to improve your timing more.

Math section in a competitive exam is the most important part of the exam. It doesn’t mean that other topics are not so important. But only math portion can leads you to a good score. A good score comes with practice and practice. You should do your math problems within time with correctness, and this can be achieved only by using shortcut tricks. But it doesn’t mean that you can’t do math problems without using any shortcut tricks. You may have that potential that you may do maths within time without using any shortcut tricks. But so many other people may not do the same. So percentage shortcut tricks here for those people. We always try to put all shortcut methods of the given topic. But we may miss few of them. If you know anything else rather than this please do share with us. Your little help will help so many needy.

This type of problem are given in Quantitative Aptitude which is a very essential paper in banking exam. Under below given some more example for your better practice. when we say 100 percent in mathematical notation we write 100% so 35 % means 35 per 100 and 65% means 65 per 100 it is a proportion per hundred and it is used to find marks, profit percent or loss percent of a particular product. it is also used in find out the depreciation at the rate percent per annul.

 

 

Example #1
The difference between 44% and 32% of that number is 26400. What would be the 60% of that number?

Answer
Difference = (44% – 32%) = 12%
12% = 26400
So, 60% = 26400 x 60 / 12 = 132000.

 

Example #2
1/2 of 1/5 of a number is 16. What would be the 20% of that number?

Answer
Let, the number be X.
(1 x 1 x X) / (2 x 5) = 16
X = 160
So, 160 of 20% = 160 x 20 / 100 = 32%.

 

Example #3
In a Kaziranga National Park were 960 one-horned rhinoceros in last year. This year their number are increased by 20%. How many tiger are there in Kaziranga National Park in this year?

Answer
950 x 120 / 100 = 1140.

 

Example #4
In class test to get pass marks 40%, Jatin got 525 marks and failed by 56 marks. Find the maximum marks in the class test.

Answer
525 + 56 = 576
Maximum marks of class test = 100 x 576 / 40 = 1440.

 

Example #5
A boy sold two books for Rs. 990 each. On one he lost 10% and on another he gained 10%. Find the total profit % of the loss %.

Answer
There is always a loss in this case
Loss% = 102 / 100 = 1

 

Example #6
The monthly salary of a labour is increased by 30% and he gets Rs. 36 per month. What was his daily salary before increasing?

Answer
100 x 26 / 130 = Rs.20

 

Example #7
Due to reduction of price 30% of pineapple Rajesh to bought 31 pineapples more Rs. 620. What would be the reduced price of 20 pineapples?

Answer
Saving = 620 x 30 / 100 = Rs.186
Reduced price per pineapple = 186 / 31 = Rs.6
Reduced price 20 pineapple = 6 x 20 = Rs.120

 

Example #8
Ajit spends his 35% on food, 20% on rent, 15% on mobile recharge and 18% on cloths. After all his expenses at last he saved Rs. 8400. How much money he spent on cloths?

Answer
Total Expenses (35 + 20 + 15 + 18)% = 88%
Spent on cloths = 18 x 8400 / 12 = Rs. 12600

 

Example #9
If the salary of Sayan is 15% more than of Koushik’s salary. How much % Koushik’s salary is less than that of Sayan’s salary?

Answer
15 x 100 / 100 + 15 = 1500 / 115 = 131/23%

 

Example #10
In a class test it is required to pass marks aggregate is 65%. A student gets 720 marks and is declared as failed by 5% marks. Find the maximum aggregate marks a student.

Answer
60% = 720
100% = ?
720 x 100 / 60 = 1200
The maximum aggregate marks is 1200.

 

Example #11
Because of 20% decreases in the price of a item, its consumption will increases by 30%, What effect would be the profit he got?

Answer
Formula: X + Y + (XY/100)
-20% + 30% + (-20%)x(+30%)/100
10% + (-6%) = 4%

 

 

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