Problems Based on after years Ages Shortcut Tricks


Problems Based on after years Ages Shortcut Tricks
Problem based on after years Ages is an very important topic which is given most of the competitive exams.You can easily solve all kind of Aptitude questions based on Problems on after years Ages by practicing regularly.

Before going to solve the problem on ages you need to know the linear equation which help in math but first you are do traditional process than you learn problem on ages shortcut tricks or ages shortcut tricks . This type of problem are given in Quantitative Aptitude which is a very essential paper in banking exam . Under below  given some more example for your better practice.

Shortcut tricks on problems based on after years ages are one of the most important topics in exams. Time is the main factor in competitive exams. If you manage your time then you can do well in those exams. Most of us miss that part. We provide examples on Problems Based on after years Ages shortcut tricks here in this page below. All tricks on problems based on after years ages are provided here. Visitors please read carefully all shortcut examples. You can understand shortcut tricks on Problems Based on after years Ages by these examples.

First of all do a practice set on math of any exam. Write down twenty math problems related to this topic on a page. Using basic math formula do first ten maths of that page. You also need to keep track of the time. After solving all ten math questions write down total time taken by you to solve those questions. Now read our examples on problems based on after years ages shortcut tricks and practice few questions. After finishing this do remaining questions using Problems Based on after years Ages shortcut tricks. Again keep track of Timing. You will surely see the improvement in your timing this time. But this is not enough. If you need to improve your timing more then you need to practice more.

We all know that the most important thing in competitive exams is Mathematics. That doesn’t mean that other sections are not so important. But only math portion can leads you to a good score. A good score comes with practice and practice. The only thing you need to do is to do your math problems correctly and within time, and only shortcut tricks can give you that success. But it doesn’t mean that you can’t do math problems without using any shortcut tricks. You may have that potential to do maths within time without using any shortcut tricks. But other peoples may not do the same. So Problems Based on after years Ages shortcut tricks here for those people. We try our level best to put together all types of shortcut methods here. But it possible we miss any. We appreciate if you share that with us. Your help will help others.

 

 


Example #1
The ratio of ages of Rahul and Raju is 5 : 6. If their age difference is 9 years, find the sum of their ages after 8 years.

  1. 111 Years
  2. 115 Years
  3. 125 Years
  4. 100 Years

Show Answer Show How to Solve Open Rough Workspace

Answer: Option (B)
How to Solve
( 9 x 5 + 8 ) + ( 9 x 6 + 8 ) = 53 + 62 = 115 years.
Rough Workspace

Example #2
Four years ago the age ratio between Naren and Kunal was 5 : 6. Present age ratio between Naren and Kunal is 12 : 15 respectively. What would be Naren age after 7 years?

  1. 40 Years
  2. 45 Years
  3. 50 Years
  4. 55 Years

Show Answer Show How to Solve Open Rough Workspace

Answer: Option (D)
How to Solve
5x + 4/6x + 4 = 12 / 15
72x + 48 = 75x + 60
3x = 12
x = 4

So, After 7 years Naren’s age would be 4 x 12 + 7 = 55 years.

Rough Workspace

Example #3
The age ratio between Rima and Rohit is 4 : 7. Sum of their ages is 77 years. What would be the ratio of their ages after 7 years?

  1. 5 : 8
  2. 8 : 5
  3. 3 : 7
  4. 7 : 3

Show Answer Show How to Solve Open Rough Workspace

Answer: Option (A)
How to Solve
Let, age of Rima and Rohit is 4x and 7x.
So, 4x + 7x = 77
x = 7

So, their Ratio would be
4 x 7 + 7 / 7 x 7 + 7
= 35 / 56
= 5 / 8
= 5 : 8

Rough Workspace

Example #4
The ratio of ages of Nitin and Naren is 5 : 4 and their age difference is 7 years. What would be the sum of their ages after 8 years?

  1. 49 Years
  2. 59 Years
  3. 69 Years
  4. 79 Years

Show Answer Show How to Solve Open Rough Workspace

Answer: Option (D)
How to Solve
(5 x 7 + 8) + (4 x 7 + 8)
= 43 + 36
= 79 years.
Rough Workspace

Example #5
The sum of present ages of a father and his son is 60 years. Six years ago father’s age was five times the age of the son. What will be the age of son after six years?

  1. 16 Years
  2. 18 Years
  3. 20 Years
  4. 22 Years

Show Answer Show How to Solve Open Rough Workspace

Answer: Option (C)
How to Solve
Let present age of son and father is X and (60 – X ) years.
Then,
( 60 – X ) – 6 = 5 (X – 6 )
54 – X = 5X – 30
6X = 84
X = 14 years.

So, Son’s age after six years will be ( X + 6 ) = 14 + 6 = 20 years.

Rough Workspace

Example #6
Ratio of present ages of C and D is 4 : 6. The present age of C is 40 years. Find the age of D after 6 years.

  1. 49 Years
  2. 66 Years
  3. 72 Years
  4. 84 Years

Show Answer Show How to Solve Open Rough Workspace

Answer: Option (B)
How to Solve
Let, the ages of C and D are 4X and 6X.
Hence,
C = 4X = 40

X = 10, ( So, we get the value of X )

So, the present age of D is
6x = 6 x 10 = 60 years

Hence, the age of D after 6 years will be 60 + 6 = 66 years.

Rough Workspace

Example #7
Six years before the ages ratio of Bikas and Suresh was 4 : 6. Present ratio of their ages is 12 : 16. What will be Suresh age after 8 years?

  1. 32 Years
  2. 28 Years
  3. 45 Years
  4. 38 Years

Show Answer Show How to Solve Open Rough Workspace

Answer: Option (A)
How to Solve
12x – 6 / 16x – 6 = 4 / 6
72x – 36 = 64x – 24
x = 3 / 2

So, ( 16 x 3 / 2) + 8 = 24 + 8 = 32 years.

Suresh age after 8 years is 32 years.

Rough Workspace

Example #8
The ratio of present ages of two students is 1 : 2. 5 years back the ratio was 1 : 3. What will be the ratio of their ages after 5 years?

  1. 5 : 3
  2. 3 : 5
  3. 3 : 8
  4. 8 : 3

Show Answer Show How to Solve Open Rough Workspace

Answer: Option (B)
How to Solve
Let, the present ages of the two students be X years and 2X years respectively.
Then,
X – 5 / 2X – 5 = 1 / 3
3 ( X – 5 ) = ( 2X – 5 )
X = 10

So, after 5 years their age ratio will be ( X + 5 ) : ( 2X + 5 ) = 15 : 25 = 3 : 5.

Rough Workspace

Example #9
The ratio between the present ages of A and B is 6 : 7. If B is 4 years older than A, what will be the ratio of the ages of A and B after 4 years?

  1. 8 : 7
  2. 7 : 8
  3. 3 : 7
  4. 7 : 3

Show Answer Show How to Solve Open Rough Workspace

Answer: Option (B)
How to Solve
Let, the A’s age and B’s age be 6X and 7X years respectively.
Then,
7X – 6X = 4
X = 4

So, their age after 4 years will be ( 6X + 4 ) : ( 7X + 4 ) = 28 : 32 = 7 : 8.

Rough Workspace

Example #10
The ratio of mother’s age to his son’s age is 7 : 3. The product of their ages is 756. The ratio of their ages after 6 years will be?

  1. 7 : 5
  2. 3 : 1
  3. 2 : 1
  4. 1 : 4

Show Answer Show How to Solve Open Rough Workspace

Answer: Option (C)
How to Solve
Step 1 :Let the present ages of the mother and son be 7X and 3X years respectively .
Then , 7X x 3X = 756
21X2 = 756
X2 = 36
X = 6

So, their age after 6 years will be (7X + 6 ) : ( 3X + 6 ) = 48 : 24 = 2 : 1.

Rough Workspace

Few other examples of Problems Based on Ages

 

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9 comments

  1. leetesh says:

    Problems Based on after years Ages Shortcut Tricks
    Can you please workout few more examples and upload here, so that it can be useful for us!
    I feel that i miss one small trick in the above topic especially to find out the ages of father and son.
    So few more examples would be worthwhile and helpful.
    Thank you

  2. manjari kumari says:

    DEAR SIR/MAM
    I’M REALLY VERY HAPPY TO LEARN THE SUM OF PROBLEM OF AGES THROUGH YOUR TRICK. . AND THANKS FOR THESE SOLUTION.

  3. Priya verma says:

    Aperson present age is two- fifth of the age of his mother . After 8 yrs , he will be one-half of the age of his mother . How old is the mother at present?

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