Now here we will discuss few question answers on Letters arrangement which are very common in competitive exams. These Letters arrangement practice question answer session will help you to prepare for your examination. Your math skills is very much needed to solve this kind of problems. Shortcut tricks can also be used to solve these Letters arrangement questions.

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A question on Letters arrangement will be discuss here. All you need to do is to read the question very carefully and try to solve it by yourself. Answer of this question will be provided along with examples. If you do this problem then check the solution of this question with your answer. If you don’t know how to solve this then also check below.

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**Problems on different ways of Letter arrangement questions and answers**

**Example 1:** In How many different ways can the letters of the word ” STUDENT ” be arranged ?

**Answer :** Total ways = STUDENT = 71 = 7 x 6 x 5 x 4 x 3 x 2 x 1 = 5040.

**Example 2:** Find in how many different way the word “APPLE” be arranged ?

**Answer :** The total ways of arrangements is = 5! = 5 x 4 x 3 x 2 x 1 = 120.

**Example 3:**

Find in how many different way the word “LEARNER” be arranged ?

**Answer :**

The total ways of arrangements is = 7! = 7 x 6 x 5 x 4 x 3 x 2 x 1 = 5040.

**Example 4:**

Find in how many different way the word “DANGER” be arranged ?

**Answer :**

The total ways of arrangements is = 6! = 6 X 5 X 4 X 3 X 2 X 1 = 720.

**Example 5:**

Find in how many different way the word “LAPTOP” be arranged ?

**Answer :**

The total ways of arrangements is = 6! = 6 X 5 X 4 X 3 X 2 X 1 = 720.

**Example 6:** Find in how many different way the word “INDIA” be arranged ?

**Answer :** The total ways of arrangements is = 5! = 5 X 4 X 3 X 2 X 1 = 120.

**Example 7:** Find in how many different way the word “BOLLYWOOD” be arranged ?

**Answer :** The total ways of arrangements is = 9! = 9 X 8 X 7 X 6 X 5 X 4 X 3 X 2 X 1 = 362880.

**Example 8:** How many different way can be formed by using all the letters of the words “FEBRUARY” so that the vowels always come together ?

**Answer:** The word contains 8 different letters. In this word vowel letter present “EUA”, we consider it as one letter.

So, letter be arrange as FBRRY (EUA).

We can arrange 5 letters as ^{6}P_{6} = 6! = 6 x 5 x 4 x 3 x 2 x 1 = 720 ways.

we can arrange vowel as 3! = 3 x 2 x 1 = 6 ways.

So required number of words = (720 x 6) = 4320.

**Example 9:** How many different way can be formed by using all the letters of the words “COMPUTER” so that the vowels always come together ?

**Answer:** The word contains 8 different letters. In this word vowel letter present “OUE”, we consider it as one letter.

So, letter be arrenge as CMPTR (OUE).

We can arrenge 6 letters as ^{6}P_{6} = 6! = 6 x 5 x 4 x 3 x 2 x 1 = 720 ways.

we can arrenge vowel as 3! = 3 x 2 x 1 = 6 ways.

So required number of words = (720 x 6) = 4320 ways.

**Example 10:** How many different way can be formed by using all the letters of the words “KEYBOARD” so that the vowels always come together ?

**Answer:** The word contains 8 different letters. In this word vowel letter present “EOA”, we consider it as one letter.

So, letter be arrange as KYBRD (EOA).

We can arrange 6 letters as ^{6}P_{6} = 6! = 6 x 5 x 4 x 3 x 2 x 1 = 720 ways.

we can arrange vowel as 3! = 3 x 2 x 1 = 6 ways.

So required number of words = (720 x 6) = 4320 ways.

**Example 11:** How many different way can be formed by using all the letters of the words “SISTER” so that the vowels always come together ?

**Answer:** The word contains 6 different letters. In this word vowel letter present “IE”, we consider it as one letter.

So, letter be arrange as SSTR (IE).

We can arrange 6 letters as ^{5}P_{5} = 5! = 5 x 4 x 3 x 2 x 1 = 120 ways.

we can arrange vowel as 2! = 2 x 1 = 2 ways.

So required number of words = (120 x 2) = 240 ways.

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Please explain Letter

LEARNER

please say me the different arrangement of letters solutions because i just confused in that……..

the solution given is without repitation.if you want with repitation you have to divide with factorial(each repited character)

send me ur no i will sent a no of tricks to u

i find it awsme

i watched your lessons in youtube i liked so….

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i likes this site and helpful to my home preparation.and u send me new trick my email id for my preparation.

Sir You can increase the content with different models

there are many models except these.