## Sum of all odd numbers starting from 1

Shortcut Tricks are very important things in competitive exam. Time is the main factor in competitive exams. If you know how to manage time then you will surely do great in your exam. Most of us miss that part. We provide examples on Sum of all odd numbers starting from 1 shortcut tricks here in this page below. We try to provide all types of shortcut tricks on sum of all odd numbers starting from 1 here. Visitors are requested to carefully read all shortcut examples. These examples will help you to understand shortcut tricks on Sum of all odd numbers starting from 1.

Before doing anything we recommend you to do a math practice set. Write down twenty math problems related to this topic on a page. Do first ten maths using basic formula of this math topic. You also need to keep track of timing. Write down the time taken by you to solve those questions. Now go through our page for sum of all odd numbers starting from 1 shortcut trick. After finishing this do remaining questions using Sum of all odd numbers starting from 1 shortcut tricks. Again keep track of timing. You will surely see the improvement in your timing this time. But this is not enough. You need more practice to improve your timing more.

### Few Important things to Remember

Math section in a competitive exam is the most important part of the exam. It doesn’t mean that other topics are not so important. You can get a good score only if you get a good score in math section. And, you can get good score only by practicing more and more. You should do your math problems within time with correctness, and only shortcut tricks can give you that success. Again it does not mean that you can’t do maths without using shortcut tricks. You may do math problems within time without using any shortcut tricks. You may have that potential. But so many people can’t do this.

Here we prepared sum of all odd numbers starting from 1 shortcut tricks for those people. Here in this page we try to put all types of shortcut tricks on Sum of all odd numbers starting from 1. But we may miss few of them. If you know anything else rather than this please do share with us. Your little help will help so many needy.

In Addition numbers shortcut tricks we learned how to find the sum of consecutive number in a group following each other continuously. that we simple way learned that problems using shortcut tricks. Now we learn how to find the sum of all odd numbers starting from 1 to 100 using short cut tricks.

This is the sum of all odd number present in 1 to 100 series numbers, we know that in 1 to 100 series number have fifty even and fifty will be odd number so we can do only half odd numbers.

### Tricks

We just follow the rule like n x n = result, Square the quantity of numbers in the series.

### Example #1 – Sum of all Odd Numbers Starting from One

Find the Sum of all Consecutive numbers in a group of 1 to 90.

- 2025
- 2041
- 2068
- 2089

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (A)

**How to Solve**

- Count the total odd numbers exists in between 1 to 90. Here it is 45.
- Multiply 45 x 45 = 2025

So, the sum of all odd numbers from 1 to 90 is**2025**.

**Rough Workspace**

### Example #2 – Sum of all Odd Numbers Starting from One

Find the Sum of all Consecutive numbers in a group of 1 to 60.

- 880
- 890
- 900
- 910

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (C)

**How to Solve**

- Count the total odd numbers exists in between 1 to 60. Here it is 30.
- Multiply 30 x 30 = 900

So, the sum of all odd numbers from 1 to 60 is**900**.

**Rough Workspace**

### Example #3 – Sum of all Odd Numbers Starting from One

Find the Sum of all Consecutive numbers in a group of 1 to 70.

- 1209
- 1225
- 1247
- 1271

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (B)

**How to Solve**

- Count the total odd numbers exists in between 1 to 70. Here it is 35.
- Multiply 35 x 35 = 1225

So, the sum of all odd numbers from 1 to 70 is**1225**.

**Rough Workspace**

### Example #4 – Sum of all Odd Numbers Starting from One

Find the Sum of all Consecutive numbers in a group of 1 to 30.

- 210
- 215
- 220
- 225

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (D)

**How to Solve**

- Count the total odd numbers exists in between 1 to 30. Here it is 15.
- Multiply 15 x 15 = 225

So, the sum of all odd numbers from 1 to 30 is**225**.

**Rough Workspace**

### Example #5 – Sum of all Odd Numbers Starting from One

Find the Sum of all Consecutive numbers in a group of 1 to 80.

- 1600
- 1623
- 1641
- 1669

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (A)

**How to Solve**

- Count the total odd numbers exists in between 1 to 80. Here it is 40.
- Multiply 40 x 40 = 1600

So, the sum of all odd numbers from 1 to 80 is**1600**.

**Rough Workspace**

### Few examples of Addition Shortcut Tricks

- Similar Digit Numbers Addition Shortcut trick
- Addition of Similar Digit with Decimal Numbers Shortcut tricks
- Addition of number without Decimal in First number
- Without Decimal in second number Addition
- Addition of common difference in a series of numbers shortcut tricks
- Sum of all consecutive numbers starting from 1
- Addition of consecutive numbers shortcut tricks
- Addition combination of decimal and whole no Tricks
- << Go back to Addition Shortcut main page

We provide few tricks on Addition. Please visit this page to get updates on more Math Shortcut Tricks. You can also like our facebook page to get updates.

If you have any question regarding this topic then please do comment on below section. You can also send us message on facebook.

How to solve 1^2+3^2+5^2+….19^2=?

Please reply fast

Answer is 1300 how i don’t have any idia

(19*20*21)/6 =1330

find sigma( 2n -1)^2 limits from 1 to 19

since the base are odd numbers ,and general form of odd number is 2n-1 ,if we consider n start from 1 or 2n+1 if we consider n starts from 0,

so, lower limit is 1 if we take 2n-1,and upper limit will be 2n-1=19 so, n=10 that is the upper limit not

using sigma operation add this

like summation of (2n-1)(2n-1)=4n^2-4n+1 (A)

now put n=1,2,3…10 and then add for every n in the eqn(A)