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Miscellaneous Examples

Last Modified on August 10, 2022 by Admin

We all know that the most important thing in competitive exams is Mathematics. It doesn’t mean that other topics are not so important. You can get a good score only if you get a good score in math section. You can get good score only by practicing more and more. All you need to do is to do math problems correctly within time, and you can do this only by using shortcut tricks. But it doesn’t mean that without using shortcut tricks you can’t do any math problems. You may have that potential to do maths within time without using any shortcut tricks. But so many people can’t do this. Here we prepared miscellaneous examples for those people. Here in this page we try to put all types of Miscellaneous Examples. But it possible we miss any. We appreciate if you share that with us. Your little help will help so many needy.

Example 1:
The area of a square is twice the area of a rectangle.If the area of the square is 324 Sq.Cms, and the length of the rectangle is 13.5 Cm, What is the difference the breadth of the rectangle and the side of the square?

Answer :
We know the formula of square a² = 324,so side of square a = 18 Cm.
length of rectangle is 13.5 Cm,
breadth = ?
324 = 2(l+b)
324 = 2 x (13.5 + b)
b = 324 x 10 / 2 x 135
b = 12
So the difference between breadth of the rectangle and the side of the square is ( 18 – 12 )=6 Cm.

Example 2:
What is area ? If the circumference of a circle is 22 Cm.
Answer :
circumference = 22 Cm
22 = 2 x 22 x r / 7
r = 7 / 2 cm.
Area of circle =πr²
22 x 7 x 7 / 7 x 2 x2 = 38.5 Cm²

Example 3 :
If the base of a triangular stadium field is 750 meters and its height 550 meters, Find the area of the field.
Answer :
Shortcut tricks :
Area of the field = Base x Height / 2
So , 750 x 550 / 2 square meters
= 375 x 550 / 100 x 100 = 20.625 sq. hectometers,

Example 4 :
If the base of a triangular stadium field is 750 meters and its height 550 meters. Find the area of the field. Along with also find the cost for maintenance to the stadium field at the rate of Rs 35.25 per sq.
Answer :
Shortcut tricks :
Area of the field = Base x Height / 2
So, 750 x 550 / 2 square meters
= 375 x 550 / 100 x 100 = 20.625 sq. hectometers ,
So, Cost of maintenance of stadium field 1 sq. hectometers = 35.25.
= Rs, 20.625 x 35.25 = Rs , 727.03125.
the cost for maintenance to the stadium field is Rs , 727.03125.

Example 5 :
The area of a rectangle 18 meters 2 decimeters long and 15 meters 3 decimeters wide. Find the area of square.
Answer :
Length = 18.2 meters.
Breadth = 15.3 meters.
So the area of square is ( Length x Breadth ) = 18.2 x 15.3 = 278.46 square meters.

Example 6:
In a hall room has the floor which is 30 meters long and 10 meters broad So, How many meters of cotton carpet 75 cm wide will be required to cover the room of hall and how much amount will require to be spent on cotton carpet if available at Rs 25/- per meters ?
Answer :
Shortcut tricks :
length required = ( length of room x breadth of room / width of carpet ) = ( 30 x 10 / 75 ) = 400
Amount = rate per meter x ( length of room x breadth of room / width of carpet ) = 25 x ( 30 x 10 / 75 ) = 25 x 400 = 10000.

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