Shortcut Tricks are very important things in competitive exam. Time takes a huge part in competitive exams. If you know how to manage time then you will surely do great in your exam. Most of us miss that part. We provide examples of Problem on Speed of Train shortcut tricks here in this page below. These shortcut tricks cover all sorts of tricks on Speed of train. We request all visitors to read all examples carefully. You can understand shortcut tricks on Speed of train by these examples.

First of all do a practice set on math of any exam. Write down twenty math problems related to this topic on a page. Using basic math formula do first ten maths of that page. You also need to keep track of the time. After finish write down total time taken by you to solve those ten maths. Now practice our shortcut tricks on speed of train and read examples carefully. After doing this go back to the remaining ten questions and solve those using shortcut methods. Again keep track of Timing. You will surely see the improvement in your timing this time. But this is not all you want. If you need to improve your timing more then you need to practice more.

Few Important things to Remember

We all know that the most important thing in competitive exams is Mathematics. That doesn’t mean that other topics are less important. You can get a good score only if you get a good score in math section. You can get good score only by practicing more and more. The only thing you need to do is to do your math problems correctly and within time, and only shortcut tricks can give you that success. Again it does not mean that you can’t do maths without using shortcut tricks. You may have that potential that you may do maths within time without using any shortcut tricks.

But, so many people can’t do this. Here we prepared speed of train shortcut tricks for those people. Here in this page we try to put all types of shortcut tricks on Speed of train. But it possible we miss any. We appreciate if you share that with us. Your little help will help so many needy.

The problem on trains are important chapter for easily get the marks in competitive exam papers. you just remember the way of train cross the object and speed, time and distance. There are train based problem based on two object, Here we learn the problem on speed taken by train pass a pole, a man or light lamp or platform bridge. First is Train and second object is that which is crossed by the train.

Example #1 – Problem on Speed of Train

A 270 meters long train passes a bridge of thrice of it’s length, in 30 seconds. Find the speed of the train in km/hr.

101.5 km/hr

114.6 km/hr

122.7 km/hr

129.6 km/hr

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Answer: Option (D)

How to Solve Total size of the Bridge is (270 x 3) = 810 meters. Size of the train is 270 meters. Therefore, total distance covered by the train is: 810 + 270 = 1080 meters.

So, the speed of the train is: = 1080 / 30 = 36 m/sec.

Now, converting the speed form m/sec to km/hr, 36 x 18 / 5 = 129.6 km/hr.

Rough Workspace

Example #2 – Problem on Speed of Train

A 720 meters long train crosses a man in 60 seconds. What would be the speed of the train?

12 m/sec

13 m/sec

14 m/sec

15 m/sec

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Answer: Option (A)

How to Solve Speed = Distance / Time So, Speed = 720 / 60 Therefore, Speed = 12 m/sec.

Rough Workspace

Example #3 – Problem on Speed of Train

A super fast train of 140 meter long crossing a long tunnel of 450 meter in 20 seconds. What would be the speed of the train?

25.6 m/sec

29.5 m/sec

35.7 m/sec

38.9 m/sec

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Answer: Option (B)

How to Solve Speed = Distance 1 + Distance 2 / Time So, Speed = ( 140 + 450 ) / 20 And, Speed = 590 / 20 Finally, Speed = 29.5 m/sec.

Rough Workspace

Example #4 – Problem on Speed of Train

A local train of 150 meter long passes a boy, running at speed of 3 km/hr in the same direction, in 10 seconds. What would be the speed of the train?

45 km/hr

52 km/hr

57 km/hr

60 km/hr

Show AnswerShow How to SolveOpen Rough Workspace

Answer: Option (C)

How to Solve Speed of the train relative to man = 150 / 10 = 15 m/sec.

Convert meters to km = 15 x 18 / 5 = 54 km/hr.

Let, the speed of the train be X km/hr. So, X – 3 = 54 X = 57 km/hr.

Rough Workspace

Example #5 – Problem on Speed of Train

A jet plane covers a certain distance at a speed of 275 km/hr in 5 hours. To cover the same distance in 7 / 3 hours, at what speed it should travel of?

555.7 km/hr

567.7 km/hr

578.4 km/hr

589.2 km/hr

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Answer: Option (D)

How to Solve Speed of the jet plane is 275 km/hr. So, Distance = ( 275 x 5 ) = 1375 km.

We know that, Speed = Distance / Time So, Speed = 1375 x 3 / 7 = 4125 / 7 = 589.2 km/hr.

Rough Workspace

Example #6 – Problem on Speed of Train

A bus passes a distance of 750 km in 15 hours. What would be speed of the bus?

50 km/hr

55 km/hr

60 km/hr

65 km/hr

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Answer: Option (A)

How to Solve Speed = Distance / Time Speed = 725 / 15 = 50 km/hr.

Rough Workspace

Example #7

A 150 meter long train takes 30 seconds to cross a man standing on a platform. What would be the speed the of train?

4 m/sec

5 m/sec

7 m/sec

9 m/sec

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Answer: Option (B)

How to Solve Distance = 150 meter. Time = 30 Seconds.

We know that, Speed = Distance / Time Speed = ( 150 / 30 ) m/sec = 5 m/sec.

Rough Workspace

Example #8

A 320 meter long mail train, whose average speed was 90 km/hr, passes a platform in 40 seconds. A boy passes the same platform in 5 minutes. Find the speed of the boy in meter/sec.

2.27 m/sec

2.96 m/sec

3.03 m/sec

3.49 m/sec

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Answer: Option (A)

How to Solve At first we convert km/hr to m/sec = 90 x 5 / 18 = 25 m/sec.

Let, the size of the platform is X. So, 25 = 320 + X / 40 X = 1000 – 320 X = 680 meter.

5 minute = 5 x 60 = 300 seconds. So, Speed of boy is: 680 / 300 = 2.27 m/sec.

Rough Workspace

Example #9

A slow local train, whose length is 150 meter, crosses a bridge, whose length is 550 meter, in 50 seconds. What is the speed of the train?

11 m/sec

14 m/sec

18 m/sec

21 m/sec

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Answer: Option (B)

How to Solve At first we add the length of both the train and the bridge, i,e, 150 + 550 = 700 meter.

We know that, Speed = Distance / Time So, Speed = 700 / 50 Therefore, Speed = 14 m/sec.

Rough Workspace

Example #10

A train of 165 meters long crosses a electric post in 5 seconds. The speed of the trains in km/hr is?

100.2 km/hr

108.4 km/hr

113.7 km/hr

118.8 km/hr

Show AnswerShow How to SolveOpen Rough Workspace

Answer: Option (D)

How to Solve Distance = 165 meter. Time = 5 seconds.

We know that, Speed = Distance / Time So, Speed = ( 165 / 5 ) m/sec = 33 m/sec.

Convert m/sec into km/hr 33 x 18 / 5 = 594 / 5 = 118.8 km/hr. Speed of the train is 118.8 km/hr.

Rough Workspace

Example #11

A boy is standing on a railway bridge which is 150 meter long. He find that a train passes the bridge in 40 seconds but the train himself in 10 sec, Find the length of the train and speed.

18 km/hr

21 km/hr

25 km/hr

29 km/hr

Show AnswerShow How to SolveOpen Rough Workspace

Answer: Option (A)

How to Solve First of all, we find the length of train, We assume that the length of the train be X meters. Then, X / 10 = X + 150 / 40 40X = 10X + 1500 30X = 1500 X = 50 meter.

Now, the speed of the train is: Speed = Distance / Time So, Speed = 50 / 10 Therefore, Speed = 5 m/sec

So, convert 5 m/sec into km/hr 5 x 18 / 5 = 18 km/hr.

So, speed of the train is 18 km/hr.

Rough Workspace

Few examples of Problems on Trains with Shortcut Tricks

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10 comments

sivaprakash says:

problems on speed by train problem 1. kindly confirm the answer.

length of the train is 270 mtrs length of the bridge is thrice the length of train hence 270*3=810 now length of both = 810+270=1080 speed =distance/ time speed= 1080/30=36 m/s now change it into km/h :0

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problems on speed by train problem 1.

kindly confirm the answer.

YEs I do have a same doubt in answer of que1 please confirm.

length of the train is 270 mtrs

length of the bridge is thrice the length of train hence 270*3=810

now

length of both = 810+270=1080

speed =distance/ time

speed= 1080/30=36 m/s

now change it into km/h :0

length of the train= 270mtrs

length of the bridge is thrice the length of train hence

270*3= 810

Now,

length of both = 810+270=1080

speed =distance/time

speed= 1080/30= 36 m/s

Now change it into km/h ðŸ™‚

Its perfectly correct. Convert m/s into km/hr.

Very useful to me

very usefull …

good

first quetions of the answer is corrct

its very easy trick