## Speed Time and Distance Example 2

Speed Time and

First of all do a practice set on math of any exam. Then find out twenty math problems related to this topic and write those on a paper. Solve first ten math problems according to basic math formula. You also need to keep track of timing. Write down the time taken by you to solve those questions. Now go through our page for speed time and distance shortcut trick. After finishing this do remaining questions using Speed Time and Distance shortcut tricks. Again keep track of timing. The timing will be surely improved this time. But this is not all you want. If you need to improve your timing more then you need to practice more.

### Few Important things to Remember

You all know that math portion is very much important in competitive exams. That doesn’t mean that other topics are less important. But only math portion can leads you to a good score. Only practice and practice can give you a good score. You should do your math problems within time with correctness, and only shortcut tricks can give you that success. Again it does not mean that you can’t do maths without using shortcut tricks. You may have that potential that you may do maths within time without using any shortcut tricks. But so many other people may not do the same. For those we prepared this speed time and distance shortcut tricks. We try our level best to put together all types of shortcut methods here. But it possible we miss any. We appreciate if you share that with us. Your help will help others.

### Speed Time and Distance Example 2

Here is some example of speed and distance of example 2. This is the basic theory of Speed Time and Distance which is applied in question to obtain answers here is Speed Time and Distance Methods of example 1 in different form of examples.

In maths exam papers there are two or three question are given from this chapter. This type of problem are given in Quantitative Aptitude which is a very essential paper in banking exam. Under below given some more example for your better practice.

### Basic formula of Speed and Distance

**Distance = Speed x Time**

**Speed = Distance / Time**

**Time = Distance / Speed**

### Example #1

A boy without any stoppage driving on a road at an average speed of 80 km/hr. With stoppage he covers the same distance at an average speed of 60 km/hr. How many minutes per hour does the boy stopped?

- 12 Minutes
- 15 Minutes
- 30 Minutes
- 45 Minutes

Show Answer Show How to Solve Show Shortcut Tricks Open Rough Workspace

**Answer:**Option (B)

**How to Solve**

Let, the total distance covered by the boy on road is X km.

Time taken to complete at a speed of 80 km/hr = X / 80 hours.

Time takeen to complete at a speed of 60 km/hr = X / 60 hours.

So, he stop to rest

(X / 80) – (X / 60)

= 20X / 60 x 80

= X / 240 hours.

So, he rest per hour

(X / 240) / (x / 60)

= (X / 240) x (60 / X)

= 1 / 4 hours.

= 15 minutes.

**Shortcut Tricks**

Time of rest per hour = ( Difference of speed / Speed without stoppage )

( 80 – 60 ) / 80

= 1 / 4

= 15 minutes.

**Rough Workspace**

### Example #2

A man walking at the rate of 4km/hr to cover certain distance in 2hr 45 min. Running at a speed of 16.5 km/hr the man will cover the same distance in what time?

- 40 Minutes
- 45 Minutes
- 55 Minutes
- 60 Minutes

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (A)

**How to Solve**

Distance = Speed x Time

So, time given = 2 hr 45 min

= 2 x 60 min + 45 min

= 165 minutes OR, 165 / 60 = 11 / 4 hr.

Distance = 4 x 11 / 4

= 11 km.

So, time required to cover the distance at a speed of 16.5 km/hr is

Time = Distance / Speed

= 11 / 16.5

= 0.66 hour.

= 0.66 x 60 minutes

= 40 Minutes.

**Rough Workspace**

### Example #3

A train cover a distance of 16 km in 10 minutes. If it’s speed is decreased by 6 km/hr, then what will be the time taken by it to cover the same distance?

- 23/2 Minutes
- 29/2 Minutes
- 32/3 Minutes
- 35/3 Minutes

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (C)

**How to Solve**

Speed = (16 x 60 / 10)

= 96 km/hr.

So, after decreasing speed, the new speed is

(96 – 6)

= 90 km/hr.

So, the time taken by the train will be

16 x 60 / 90

= 32/3 minutes.

**Rough Workspace**

### Few other examples of Speed Time and Distance

- 1. Speed and Time and Example 1
- 2. Speed and Time and Distance Example 3
- 3. Speed and Time and Distance Example 4
- << Go back to Speed Time and Distance main page

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thank u so much sir

Que. 1} 1/4= 0.25

# 25 min, not 15 min

Its 1/4 hours=15min of 60min