Problem on train running opposite direction
The problem on trains are important chapter for easily get the marks in competitive exam papers.you just remember the way of train cross the object and speed, time and distance. There are train based problem based on two object,
Here we learn the problem on Problem on running opposite direction time taken by train pass a pole, a man or light lamp. First is Train and second object is that which is crossed by the train.
Shortcut Tricks are very important things in competitive exam. Competitive exams are all about time. If you manage your time then you can do well in those exams. Most of us miss that part. We provide examples on Train running opposite direction shortcut tricks here in this page below. These shortcut tricks cover all sorts of tricks on Train running opposite direction. We request all visitors to read all examples carefully. These examples here will help you to better understand shortcut tricks on train running opposite direction.
First of all do a practice set on math of any exam. Then find out twenty math problems related to this topic and write those on a paper. Do first ten maths using basic formula of this math topic. You also need to keep track of timing. After finish write down total time taken by you to solve those ten maths. Now practice our shortcut tricks on train running opposite direction and read examples carefully. After doing this go back to the remaining ten questions and solve those using shortcut methods. Again keep track of the time. This time you will surely see improvement in your timing. But this is not enough. You need more practice to improve your timing more.
You all know that math portion is very much important in competitive exams. That doesn’t mean that other topics are less important. But if you need a good score in exam then you have to score good in maths. Only practice and practice can give you a good score. You should do your math problems within time with correctness, and only shortcut tricks can give you that success. Again it does not mean that you can’t do maths without using shortcut tricks. You may have that potential to do maths within time without using any shortcut tricks. But other peoples may not do the same. So Train running opposite direction shortcut tricks here for those people. Here in this page we try to put all types of shortcut tricks on Train running opposite direction. But it possible we miss any. We appreciate if you share that with us. Your little help will help so many needy.
Example 1: 180 meter and 120 meter mail train are running on parallel in a opposite direction at the speed of 67 km/hr and 77 km/hr respectively. Find when they cross each other ?
Answer : ( 67 + 77 )x 5 / 18 = 180 + 120 / Time
Time = 15 / 2 seconds.
Example 2: 170 meter and 130 meter long two super fast train are running in opposite direction at speed of 52 km/hr and 56 km/hr in par-allay. In What time would be they cross each other ?
Answer : Convert speed km/hr to m/sec = 52 + 56 = 108 x 5 / 18 = 30 m/sec.
Time = distance / speed = 170 + 130 / 30 = 300 / 30 = 10 sec.
So, they cross each other after 10 seconds.
A passenger train 330 meter long, Which is running at a speed of 60 Km / hr. In what time will it pass a man who is running at a speed 6 Km / hr in the opposite direction. In which the train is moving.
Answer: If direction is given in the opposite direction then we add both speed that is ( 60 + 6 ) = 66 Km / hr.
and now convert it into m / sec using 66 x 5 / 18 = 55 / 3 m / sec.
If the train time taken to passing a man who running in opposite direction, that is 55 / 3 m /sec. So we can easily get the distance of m / sec so it cover 330 meter that is = 330 x 3 / 55 = 18 sec.
Two super fast train 180 meters and 180 meters in length respectively are running in opposite directions, one at the rate of 58 km and the other at the rate of 50 km an hours. What time will they be completely clear of each other from the moment they meet ?
Two fast trains are running is opposite direction and their relative speed is = 58+50 = 108 km / hours.
So the two trains are each other meet at 108 km /hours.
108 x 5 / 18 = 30 m / sec.
So, the required time is = Total length / Relative speed = 180 + 180 / 30 = 12 secs.
Note: direction is given in the opposite direction then we add both speed
- Problem on time taken by train
- Problem on speed of train
- Problem on running same direction
- Problem on finding length of train or platform
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