Problems Based on Ages Shortcut Tricks
Shortcut Tricks are very important things in competitive exam. Time is the main factor in competitive exams. If you manage your time then you can do well in those exams. Most of us miss this thing. Here in this page we give few examples on Problems Based on Ages shortcut tricks. We try to provide all types of shortcut tricks on problems based on ages here. Visitors are requested to carefully read all shortcut examples. These examples will help you to understand shortcut tricks on problems based on ages.
Before starting anything just do a math practice set. Choose any twenty math problems and write it down on a page. Do first ten maths using basic formula of this math topic. You also need to keep track of the time. After finish write down total time taken by you to solve those ten maths. Now go through our page for problems based on ages shortcut trick. After doing this go back to the remaining ten questions and solve those using shortcut methods. Again keep track of the time. This time you will surely see improvement in your timing. But this is not enough. You need to practice more to improve your timing more.
You all know that math portion is very much important in competitive exams. It doesn’t mean that other topics are not so important. But only math portion can leads you to a good score. You can get good score only by practicing more and more. You should do your math problems within time with correctness, and this can be achieved only by using shortcut tricks. But it doesn’t mean that without using shortcut tricks you can’t do any math problems. You may have that potential that you may do maths within time without using any shortcut tricks. But so many other people may not do the same. For those we prepared this problems based on ages shortcut tricks. We try our level best to put together all types of shortcut methods here. But we may miss few of them. If you know anything else rather than this please do share with us. Your little help will help so many needy.
Now we will discuss some basic ideas of Problems based on Ages. On the basis of these ideas we will learn trick and tips of shortcut problems based on ages. If you think that how to solve problems based on ages questions using problems based on ages shortcut tricks, then further studies will help you to do so.
Problems Based on Ages Shortcut Tricks
Problem based on Ages is an very important topic which is given most of the competitive exams. You can easily solve all kind of Aptitude questions based on Problems on Ages by practicing regularly. Before going to solve the problem on ages you need to know the linear equation which help in math but first you are do traditional process than you learn ages shortcut tricks.
Anything we learn in our school days was basics and that is well enough for passing our school exams. Now the time has come to learn for our competitive exams. For this we need our basics but also we have to learn something new. That’s where shortcut tricks are comes into action.
This type of problem are given in Quantitative Aptitude which is a very essential paper in banking exam. Under below given some more example for your better practice. In competitive examination there are three situation based questions are given which is give below.
- Present Age
- Years ago Age
- Hence years Age
Few examples of Problems Based on Ages with Shortcut Tricks
Example 1: The ratio of present age of Asha & Bikash is 2 : 4 the present age of Asha is 30 years. What would be the age of Bikash after 6 years ?
Step 1: Asha : Bikash present age ratio is 2 : 4 and Asha present age = 30 years.
Step 2: Bikash present age is 30 x 4 / 2 = 60 years.
Step 3 : Bikash age after 6 years is 60 + 6 = 66 years.
Example 2 : The ratio of ages of Amir & Salman is at present 3 : 4, 5 years before that ratio was 2 : 3. What is the present age of Amir & Salman.
Step 1 : Amir : Salman present ratio is 3 : 4, 5 years before ratio 2 : 3.
Step 2 : 5 x 3 = 15 years, 5 x 4 = 20 years.
the present age of Amir & Salman is 15 years and 20 years.
Example 3: If the total ages of Amar and Bikash is 18 years more than the total age of Bikash and chayan. Chayan is how many years younger than Amar ?
Answer: ( Amar + Bikash ) – (Bikas + Chayan) = 18
Amar – Chayan = 18.
Here is some problem on ages sub link of Examples which help you better understanding.
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