Speed Time and Distance Example 2

Speed Time and Distance shortcut tricks are very important thing to know for your exams. Time takes a huge part in competitive exams. If you know time management then everything will be easier for you. Most of us skip that part. Few examples on speed time and distance shortcuts is given in this page below. These shortcut tricks cover all sorts of tricks on Speed Time and Distance. Visitors please read carefully all shortcut examples. These examples here will help you to better understand shortcut tricks on speed time and distance.

First of all do a practice set on math of any exam. Then find out twenty math problems related to this topic and write those on a paper. Solve first ten math problems according to basic math formula. You also need to keep track of timing. Write down the time taken by you to solve those questions. Now go through our page for speed time and distance shortcut trick. After finishing this do remaining questions using Speed Time and Distance shortcut tricks. Again keep track of timing. The timing will be surely improved this time. But this is not all you want. If you need to improve your timing more then you need to practice more.

You all know that math portion is very much important in competitive exams. That doesn’t mean that other topics are less important. But only math portion can leads you to a good score. Only practice and practice can give you a good score. You should do your math problems within time with correctness, and only shortcut tricks can give you that success. Again it does not mean that you can’t do maths without using shortcut tricks. You may have that potential that you may do maths within time without using any shortcut tricks. But so many other people may not do the same. For those we prepared this speed time and distance shortcut tricks. We try our level best to put together all types of shortcut methods here. But it possible we miss any. We appreciate if you share that with us. Your help will help others.

Speed Time and Distance Example 2 :
Here is some example of speed and distance of example 2. This is the basic theory of Speed Time and Distance which is applied in question to obtain answers here is Speed Time and Distance Methods of example 1 in different form of examples.

In maths exam papers there are two or three question are given from this chapter. This type of problem are given in Quantitative Aptitude which is a very essential paper in banking exam. Under below given some more example for your better practice.

 


Basic Formula of speed and distance

  • Distance = Speed x Time
  • Speed = Distance / Time
  • Time = Distance / Speed


 

 

TIME:

 

Example 1:
A boy without any stoppage running on a road at an average speed of 80 km /hr, and with stoppage he covers the same distance at an average speed of 60 km / hr. How many minutes per hour does boy stop ?
Answer :
Let the total distance cover by boy on road is x km .
Time take to complete at a speed of 80 km / hours = x / 80 hours .
Time take to complete at a speed of 80 km / hours = x / 60 hours .
So he stop to rest ( x / 80 – x / 60 ) hours = 20x / 60 x 80 = x / 240 hours .
So he rest per hour = x / 240 / x / 60 = x / 240 x 60 / x = 1 / 4 hours = 15 minutes .
Shortcut Tricks :
Time of rest per hour = ( Difference of speed / Speed without stoppage )
( 80 – 60 ) / 80 = 1 / 4 = 15 minutes.

 

 

Example 2:
A man walking at the rate of 4kmph to cover certain distance in 2hr 45 min. Running at a speed of 16.5 kmph the man will cover the same distance in what time ?
Answer:
we know the formula of
Distance = speed x Time
So, Time given = 2 hr 45 min = 2×60 min+45 min=165 min than 165 min / 60 min = 11 / 4 hr
Distance = 4 x 11 / 4 = 11 km
So, Time required to cover distance in speed of 16.5 kmph
Time = D / S = 11 / 16.5 = 40 min.

 

Example 3: A train cover a distance of 16 km in 10 minutes. If its speed is decreased by 6 km/hr the time taken by it to cover the same distance will be :
Answer : Speed = (16 x 60 / 10) = 96 km/hr.
After decreased speed new speed is = (96-6) = 90km / hr.
So, Time taken by 16 x 60 / 90 = 32 / 3 min.

 

 

 

 

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