Time and Work shortcut tricks are very important thing to know for your exams. Competitive exams are all about time. If you know time management then everything will be easier for you. Most of us miss this thing. Few examples on time and work shortcuts is given in this page below. We try to provide all types of shortcut tricks on time and work here. We request all visitors to read all examples carefully. These examples here will help you to better understand shortcut tricks on time and work.

First of all do a practice set on math of any exam. Then find out twenty math problems related to this topic and write those on a paper. Solve first ten math problems according to basic math formula. You also need to keep track of the time. Write down the time taken by you to solve those questions. Now go through our page for time and work shortcut trick. After this do remaining ten questions and apply shortcut formula on those math problems. Again keep track of the time. The timing will be surely improved this time. But this is not all you need. You need to practice more to improve your timing more.

We all know that the most important thing in competitive exams is Mathematics. That doesn’t mean that other sections are not so important. You can get a good score only if you get a good score in math section. You can get good score only by practicing more and more. All you need to do is to do math problems correctly within time, and you can do this only by using shortcut tricks. Again it does not mean that you can’t do maths without using shortcut tricks. You may have that potential that you may do maths within time without using any shortcut tricks. But so many people can’t do this. Here we prepared time and work shortcut tricks for those people. Here in this page we try to put all types of shortcut tricks on Time and Work. But we may miss few of them. If you know anything else rather than this please do share with us. Your little help will help so many needy.

Time and Work Example 1

Some important facts are needed for Time and work Problems. If a person do a piece of work which has to be require more time to complete, and capacity is limited to that person but two or more person do the same piece of work which require less time and effort is minimum.

This examples is** two person work a piece of work in same time and find out one person alone work to complete**. So here is some example 1 of this chapter related which help you better study for job preparation.

This type of problem are given in Quantitative Aptitude which is a very essential paper in banking exam. Under below given some more example for your better practice.

Example #1

Anil, Priyanka and Suresh together can complete a work in 20 minutes. If Anil and Priyanka together can complete the same work in 60 minutes, then how many time is required for Suresh alone to complete that work?

- 20 Minutes
- 30 Minutes
- 45 Minutes
- 60 Minutes

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (B)

**How to Solve**

( 1 / 20 ) – ( 1 / 60 )

= 1 / 30

= 30 minutes.

**Rough Workspace**

Example #2

P complete a work in 12 days and Q complete the same work in 16 days. Find the time required to complete the same work if they both work together.

- 33 / 5 Days
- 38 / 5 Days
- 38 / 7 Days
- 48 / 7 Days

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (D)

**How to Solve**

Work done by P in 1 day is 1 / 12.

Work done by Q in 1 day is 1 / 16.

Work done by ( P + Q ) together in 1 day is-

(1 / 12) + (1 / 16)

= 7 / 48.

So, together they will complete the work in 48 / 7 days.

**Rough Workspace**

Example #3

A, B and C together can finish a piece of work in 50 minutes. A and B together finish the same work in 60 minutes. In how many minutes can C alone finish that work?

- 110 Minutes
- 300 Minutes
- 500 Minutes
- 600 Minutes

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (B)

**How to Solve**

( 1 / 50 ) – ( 1 / 60 ) = 300 minutes.

**Rough Workspace**

Example #4

A can do a piece of work in 12 days and B can do a piece of work in 4 days. Find how many days they can complete that work if they work together?

- 3 Days
- 5 Days
- 7 Days
- 8 Days

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (A)

**How to Solve**

A’s 1 day work = 1 / 12

B’s 1 day work = 1 / 4

( 1 / 12 + 1 / 4 )

= 4 / 12

= 1 / 3.

So, by working together, they complete the work in 3 days.

**Rough Workspace**

Example #5

A, B and C together can complete a work in 30 minutes. If A and B together do same work in 80 minutes, then how many time required for C alone to complete that work?

- 30 Minutes
- 35 Minutes
- 40 Minutes
- 48 Minutes

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (D)

**How to Solve**

(1 / 30) – (1 / 80)

= 5 / 240

= 1 / 48

= 48 minutes.

**Rough Workspace**

Example #6

A, B and C can complete a work together in 60 minutes. A and B can complete the similar work in 80 minutes. How much minutes can C take alone to complete that work?

- 160 Minutes
- 200 Minutes
- 240 Minutes
- 280 Minutes

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (C)

**How to Solve**

C alone take = 1 / 60 – 1 / 80

= 240 minutes.

**Rough Workspace**

Example #7

22 boys can complete a piece of work in 32 days. In how many days will 16 boys complete the same work?

- 44 Days
- 48 Days
- 52 Days
- 56 Days

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (A)

**How to Solve**

22 x 32 = 16 x d2

d2 = 22 x 32 / 16 = 44.

So, In 44 days 16 man can complete that work.

**Rough Workspace**

Example #8

20 labour can do piece of work in 30 days. How many days will required for 15 labour to complete double the work?

- 60 Days
- 69 Days
- 75 Days
- 80 Days

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (D)

**How to Solve**

20 labour can do a piece of work in 30 days.

Now we need to find the double of the work by 15 labour.

We use

( Labour X Working days ) = ( Labour X Working days )

20 x 30 = 15 x ?

600 = 15 x ?

? = 600 / 15

? = 40/

Now we need to double the working days, i.e, 40 x 2 = 80 days.

**Rough Workspace**

Example #9

Subir and Kabir can do a piece of work in 20 days and 12 days respectively. Subir started the work alone and then after 4 days Kabir joined him till the completion of the work. How long did the work last?

- 8 Days
- 10 Days
- 12 Days
- 20 Days

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (B)

**How to Solve**

In 4 days Subir work done = 1 x 4 / 20 = 1 / 5.

Remaining work is = ( 1 – 1 / 5 ) = 4 / 5.

Now Subir and Kabir together work done by 1 day is = ( 1 / 20 + 1 / 12 ) = 2 / 15.

Work will be done by Subir and Kabir = ( 15 / 2 x 4 / 5 ) = 6 days.

So, the total time taken = ( 6 + 4 ) = 10 days.

**Rough Workspace**

Example #10

Rajib and Rajesh together can complete a piece of work in 4 days. If Rajib alone can complete the same work in 12 days. In how many days can Rajesh alone complete that work?

- 3 Days
- 5 Days
- 6 Days
- 8 Days

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (C)

**How to Solve**

Rajib and Rajesh can do piece of work 4 days, then

First we find required 1 day time and work,

( Rajib + Rajesh ) can do piece of work in 1 days = 1 / 4.

Rajib 1 day’s work = 1 / 12.

Same work Rajesh can do in 1 day’s = ( 1 / 4 – 1 / 12 ) = 1 / 6.

So, Rajesh can alone complete the work in 6 days.

**Rough Workspace**

Example #11

25 Women can complete a work in 15 days. How many more Women needed to complete the work in 5 days.

- 30
- 40
- 50
- 75

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (C)

**How to Solve**

25 Women can complete a work in 15 days.

Women1 x working days1 = Women2 x working days2

25 x 15 = Women2 x 5

Women2 = 375 / 5 = 75.

More women needed to complete this work is = ( 75 – 25 ) = 50.

**Rough Workspace**

Example #12

8 boys can complete a piece of work in 40 hours. In how many hours will 20 boys complete that same piece of work?

- 10 Hours
- 12 Hours
- 14 Hours
- 16 Hours

Show Answer Show How to Solve Open Rough Workspace

**Answer:**Option (D)

**How to Solve**

Boy x Hour = Boy x ?

8 x 40 = 20 x ?

320 = 20 x ?

? = 320 / 20

= 16 hours.

**Rough Workspace**

### Few examples of Time and Work with Shortcut Tricks

- Time and work Examples 2
- Time and work Examples 3
- Time and Work Examples 4
- << Go back to Time and Work main page

We provide few shortcut tricks on this topic. Please visit this page to get updates on more Math Shortcut Tricks. You can also like our facebook page to get updates.

If You Have any question regarding this topic then please do comment on below section. You can also send us message on facebook.

in example 3 why 2/15 will comes on 15/2

if Subir can do piece of work in n days, then subir 1 day’s work 1 / n.

similarly subir and kabir work done by 1 days ( 1 / 20 + 1 / 12 ) = 2 / 15.

15 / 2 comes because if subir 1 days work = 1 / n, then subir finish work in n days .

thats why it 15 / 2 both person work days

Provide Trick for

A and B work in Alternet day

Questions

Please

Sunil, in that case we use the formula…

1 = n(1/a+1/b) + x(1/a)

We will try to make sure n(1/a+1/b) is 1 itself…

If not, then we add x(1/a) to the equation as remainder work which person A does alone at last day.

Solution will be (2n+x) days.

For example, if A takes 24 days, and B takes 12 days to complete a work, and they do alternate days, we will use (1/24 + 1/12) to arrive at 1/8.

1= n (1/8) + x (1/24)

We can see that if we make n as 8, we can maximise it and make x zero.

1= 8(1/8) + 0(1/24)

=8(1/8)

So, 2n+x = 2×8 + 0 = 16 days is answer, assuming A started the work first.

ya its good .we need alternative day questions

b’coz 2/15 is a work done by them in one day but we need total work of them so 2/15 is one day work than total work is 15/2

In example 1 1/50-1/60=1/300 how?

pls explain 1 of the any of the the example in details.

(1×6/50×6)-(1×5/60×5)=(6-5)/300=1/300(take LCM)

Yes you are right the ans should be 300 mins. The person who has updated this site might have forgotten to take the reciprocal…I hope i was able to help you.

All these tricks are so helpful and I’m greatly thankful to this maths site. Thankew sir

These tricks are very much helpful for me it consumes less time and so, they are very much beneficial if they are applied in any competitive exam.

I like it; helpful

I am very happy to know this trick

Really helpful…

very helpful tricks sir i m greatly thankful to you will you send some important tricks in my mail

thankyou

thx sir

these are so useful tricks.. thank u

its very useful for me

All tricks are very usefull.Thank u for all tricks

5 men can move a weight of 120 kg through distance of 5m in 10 mins.How much time will be needed by 10 men to move a weight 0f 240 kg through a distance of 15 m

30min

ITS VERY BEST TRICS THANK U

A alone can complete a work in 16 days and B alone in 12 days.Starting with A,they work on alternate days.The total work will be completed in :

let total work=lcm of16,12=48 units

one day work of a=48/16=3 units

one day work of b=48/12=4 units

total units of work=3+4=7

to do 48 units of work days required=48*2/7=13.7 aprox 14 days

A B nd C can do a piece of work in 20 30 and 60 days respectively.In how many days can A do the work if he is assisted by B and C on every 3rd day?

15 day

can you please explain the complete working of this question

\

good questions are asked

thank you very much sir now i understand maths easily.

your explanations are very helpful.

Thank you very much sir now i understand maths easily. your trick is very helpful

SIR I WANT TO KNOW MORE TRICKS RELATED FORM ALLIGATION CHAPTER

Thank you very much sir. Plz send the more problem in my email id.

(1/20+1/12)=2/15 how?

1/20+1/12=3+5/60=8/60=2/15

very very very good……

thank u very much……….

i loved it……

A = one work in 10 days

B – same work in 15 days

they work together for 5 days and then C finishes rest of the work in 2 days. In total they have been paid 1500 RS.

What would be the daily wasage of B and C

225

thank you its very help full

50 men can complete the work in 100 days.In how many days the work will be completed if 10 men joined after every 10 day.

Sir plz solve and explain this question.

Plz sir send difficult question with solution b’coz I face problem to solve difficult questions

1/20-1/60=0.033333 in first example how it is 30min

1/20-1/60 =

3/60 – 1/60 = 2/60

=1/30

This is the contribution, not time. To get time, we reverse its fraction.

1/30 is made 30/1 = 30 minutes

vishal :- 1/20 – 1/60

6 – 2 / 120 = 4 /120 = 30 min

IN EXAMPLE 11-) please explain sir,

How many more women need the complete work in 5 days ?

75-25=50

How is it possible sir, more means plus symbol then we add only 75+25=100.

please clear this doubt

Pls change the bCkground theme..

The page is not clear …

Can you help to solve a word problem? the word problem is: A and B together complete a piece of work in 20 days. The same work is completed by B and C and C and A in 15 and 12 days respectively. how long will it take for them to complete the work together? and how long will each take to complete the same work?

The work will be completed by A,B and C together is 10 days.individual work by A-30 days B-60 days C-20 days

2(A+B+C)=1/20 + 1/15 + 1/12.

you can solve it and u will get the accurate answer.

thank uu… this is very helpful

Thnku sir..really helpful

A does a work in 90 days, B in 40 days and C in 12

days. They work one after another for a day each, starting with

A followed by B and then by C. If the total wages

received are Rs 360 and A, B, C share them in the ratio

of the work done, find their respective individual wages

Sir ex 9 I can’t understand y we take 4 days as 1/4 and fully explain clearly

1 pics of work done in 4 days

1 day work is done 1/4 part of work

Here work is writen in form of 1/4

A contractor undertook to complete a work in 120 days. He employed 200 men. In 72 days only half of the work was done.How many more men should be employed to complete the work in time ?

15 men or 7 boys can do a work in 29 days, then 12 men and 8 boys will do the same work in???

in ex. 3 it would be 300 not 1/300 …

2 men and 3 boys can do a piece of work in 10 days while 3 men and 2 boys can do the same work in 8 days, in how many days can 2 men and 1 boy do the work?